public interface I1{Static String x="inside I1";public void someMethod();}class A implements I1{ public static void main(String args[[]){ System.out.println("Calling I1 var ..."+I1.x);}}

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abuthahir.d  

 Profile Answers by abuthahir.d Questions by abuthahir.d

• Member Since Jan-2008 | Apr 14th, 2008

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Compilation error due to 2 reasons.
1. All variables defined in the Interfaces are implicitly public static final. So need not specify "Static" in interface.

2. If any of the member functions of a Interface is not Overriden , a compilation error will be thrown

shanu_rastogi

 Profile Answers by shanu_rastogi Questions by shanu_rastogi

• Feb 3rd, 2010

It is right that you dont need to explicitly define a varible static but if you do so then it will not give compliler error..

sarojmohanty

 Profile Answers by sarojmohanty Questions by sarojmohanty

• Nov 19th, 2009

Compilation error will come because you must have to override the abstract method of the implememted interface. After the implementation of the abstract method the program will compile and run properly and print "inside l1".

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ashish_setia  

 Profile Answers by ashish_setia Questions by ashish_setia

• Member Since Oct-2006 | Oct 3rd, 2006

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check out this example

class Checkmain{
public static void main(String args[]){
args[1]="ashish";
System.out.println("hello ");
}
}
class Checkmain1 extends Checkmain{
public static void main(String args[]){
System.out.println("how r u");
}

}
class Jo{
public static void main(String args[]){
String S[]=new String[10] ;

Checkmain.main(S);
Checkmain1.main(S);
}}

vivek

• Aug 26th, 2017

Yes you can only do that by overriding main method signature for eg main(String[] args) to main(). Certainly there are no other ways to do that because JVM needs strings array arguments to take comma...

Dharmendra Singh

• Sep 15th, 2016

yes we can"java public class HelloWorld { // arguments are passed using the text field below this editor public static void main(String[] args) { String []s =new Str...

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