What happens if dc supply is given to a transformer?

Questions by siva.k

Showing Answers 1 - 22 of 22 Answers

boda devsingh

  • Mar 14th, 2013
 

If DC supply is given to the primary of Transformer then DC current flows through primary winding which is constant(time invarient).For production of emf in any winding the current flowing through that must be sinusoidal since e=L*(dI/dt).So in the given case ie, for DC input,no emf produced in primary winding. So net voltage in the primary winding will be (Vin-0) more due to which primary winding draws more current which leads to burning of winding.

In the case of AC voltage input emf produced in the primary,lets say e1 then net voltage in the primary is (Vin-e1) less, so the primary winding draws less current and the winding will be safe.

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Prachurjya Parashar

  • Mar 19th, 2013
 

When dc current is supplied to the X-mer, the primary side will draw a steady current due to which a constant flux is generated. Hence no back emf is produced. Thus the primary side of the X-mer which is a low resistance side draws excessive current ultimately resulting in burning out of the terminals.

Thus, to limit the effect of application of dc to X-mer a high resistance is connected in series to the primary side of the X-mer.

transformer works on the principle of mutual induction which means rate of change of current or charges induces e.m.f..
hence alternating current is the one in which current varies with respect to time and when direct current is sent to transformer there will be no change in current and no mutual induction and hence transformer doesn't work..

aniruddha mani

  • May 18th, 2013
 

The secondary winding of the tmer will burn as there is no back emf in the primary winding of the tmer.

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waris

  • Jun 25th, 2013
 

dc has no alternating waves so there is no induced emf in the secondary. so dc is applied to primary there is no impedance in the primary due to dc.hence only resistance which is very less in the tfrmr windings.due to that primary will burn out.

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I understanding what the question generally is asking, the question needs to be more specific to how the DC is being used when hooked up to a transformer. An example is a Balun which is a transformer or a coupled inductor (seen in switching power supplies, impedance matching networks ect) is used to pass DC or any current of different potentials. There is no specified voltage or current in the question so A direct current initially will "charge" or create a stored porential in the transformer and if the DC is removed it then creates a electrical current in the secondary of the transformer or "Material" in a coupled inductor. In magnetism the stored potential or Remanence is the amount of flux density which remains in the material after the external field is removed. Also when the transformer charges its resistance (or reactance) increases so it could be thought of as A open switch.

I would guess the burn up happens because no one converted the transformers designed volt-amp rating and frequency to what would be the "DC rating"; if done properly DC will make the transformer conduct then stop conducting when charged just like a capacitor. Capacitors are an analog of an inductor so too much voltage they too burn up.

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billaragu

  • Jan 29th, 2014
 

When DC current passed through the transformer.....the primary winding was burning.....

so only AC current use in the transformer......

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shobhit nagar

  • Feb 3rd, 2014
 

if we supply dc to the transformer then there will be no emf induced in the coil the emf generates only in case of ac and dc may also burn to the transformer.......

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adarsh

  • Mar 2nd, 2014
 

transformer has high inductance and low resistance. in dc supply there is no inductance only resistance will act in the circuit so high current will flows through the primary of the transformer. for this reason coil and insulation will burn out.

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chiragmistry

  • Mar 14th, 2014
 

When DC supply applied to transformer the rate of change of flux is zero so output voltage iz zero.Thats why transformer is not work on dc supply.

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VUYYURU AJAY KANTH

  • Mar 27th, 2015
 

the t/f will be short ckt .because the t/f work on mutual induction when dc supply given it acts as self induction means the primary flux will not mutual to the secondary when given dc supply at primary flux increase during some time the t/f may get damage.the alternate cycle while required in ac only not in dc.depend on the form factor the step ration will be depend .these are the main condition we are giving ac supply to the t/f

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vash

  • Mar 29th, 2015
 

because
when dc supply is applied on xmer its primary winding is burned ......
2--- cause. waveform of dc is straight line and ac waveform is alternating.. dc is not good xmer....

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timmmi khan

  • Apr 8th, 2015
 

Voltage in a transformer is developed only with a frequency. Since a dc supply has a zero frequency, voltage in a transformer will remain zero also.

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jitendra

  • Apr 25th, 2015
 

the winding will be burnt only when the current through the winding becomes so much that the winding cannot withstand it.if i apply 3v dc to a 160MVA transformer,nothing will happen to the primary winding.

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vineethprasath vcet

  • May 2nd, 2015
 

Transformer works in the mutual induction principle so AC current only use because AC source only changes with times, DC current does not change with time so transformer does not work in DC, if we passed DC in transformer the primary winding are burned

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Faran

  • May 18th, 2015
 

A constant current through the primary winding produces a non-changing magnetic field (Faradays Law). The transformer doesnt work properly since a non-changing magnetic field doesnt produce a current in the secondary winding. This is the reason why the power grid uses AC instead of DC: because transformers only operate with AC voltage and not DC.

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javed khan

  • May 25th, 2015
 

Simply and shortly the transformer working ac supply the ac flux plus and negative. And dv fluc is constant.

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Ayaz Shaik

  • Jun 29th, 2015
 

Lets us speak some think about A.C and D.C first.....A.C is a form of voltage which flows in a form of wave and has some certain amount of frequency..but D.C is completely just passage through the given media for translation...now coming to transformer for its operation basic requirement in mutual induction..

If you apply DC there would be alternating flux.. according to our basic laws any one either conductor should be in motion or magnetic field.. in transformer it is static if you apply DC it is also static them there is transformation of flux so it does not cause transformation i.e induction and further causes insulation failure.

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aneesh k

  • Jul 3rd, 2015
 

Could you please explain how the secondary winding will burn?

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Khushali Thacker

  • Jul 7th, 2015
 

AC means alternating voltage. When AC supply is given to the transformer, there will be rate of change of flux w.t.time. so EMF will be induced in the coil. If we apply DC supply, there will not be any change of flux so EMF will not be induced. If we apply DC supply then coil will come in saturation condition so we cant apply DC supply to transformer.

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DAVID

  • Jul 8th, 2015
 

Basically transformer only using in device with AC(sinusoidal), using DC in Transformer will not make transformer work. The principle of the transformer is induced magnetic field of the primary winding to the secondary winding. This induction should change and continuous. If the transformer is energized DC then there initially occurs induction but not change (aka fixed) magnetic field so that the next energized no voltage on the secondary winding.
But instead of DC current can not be entirely incorporated in the transformer, if the DC current is made pulse (on - off) is continuous with the oscillator can be energized voltage on the secondary winding.

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Dipanjan Biswas

  • Jul 13th, 2015
 

Transformer is like an inductor coil. For inductor V=L(di/dt); for DC there is no change in current, so i=constant. So (di/dt)=0; so output voltage is 0. So if DC supply is given to a transformer then output voltage will zero.

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