jbode

 Profile Answers by jbode Questions by jbode

• Oct 18th, 2011

 

This can easily be done with 3 recursive functions.

The first function will print out a sequence from 1 to n:

void printSeq1(int n)
{
if (n > 1)
printSeq1(n - 1);
printf("%d ", n);
}

The second function will print N sequences from 1, 1 2, 1 2 3, etc.:

void printSeq2(int n)
{
if (n > 1)
printSeq2(n - 1);
printSeq1(n);
}

The third function will print N sequence from 1 2 3, 1 2, etc.

void printSeq3(int n)
{
printSeq1(n);
if (n > 1)
printSeq3(n - 1);
}

Put it all together in one function:

void printSeq(int n)
{
printSeq2(n - 1);
printSeq1(n);
printSeq3(n - 1);
}

int main(void)
{
printSeq(4);
return 0;
}

Voila.

Sai Praveen Gampa

• Nov 1st, 2011

 

No need of three functions.
Good thought to use Recursive.
I have just divided that output as..
1
1 2
1 2 3
1 2 3 4
1 2 3
1 2
1

Dont mind if you want the same output as you specified just remove
printf("
");
Line from the code.

Code
#include<stdio.h>


static int temp1=1,temp2=1,n=4;


int max=0;


main()


{


 if(temp1<=temp2)


 {


  printf("%d ",temp1);


  temp1++;


  main();


 }


 else


 {


  printf("


");


  if(temp2==n)


        max=1;


  if(max==1)


  {


        if(temp2>0)


        {


                temp2--;


                temp1=1;


                main();


        }


  }


  else


  {


        temp2++;


        temp1=1;


        main();


  }


 }


}