Manohar

• Aug 5th, 2011

 

Code
# include<math.h>


main()


{


int n=153,rem,sum=0;


while(n>0)


{


rem=n%10;


sum=sum+pow(rem,3);


n=n/10;


}


printf("%d",sum);}

prabhaamca11

 Profile Answers by prabhaamca11 

• Aug 10th, 2011

 

Code
#include<stdio.h>


void main()


{


int n=370;


int a,b,c,d,e;


a=n%100;


b=n/100;


c=a%10;


d=a/10;


e=(b*b*b)+(c*c*c)+(d*d*d);


if(e==370)


 


printf("the given no is Armstrong no.%d",e);


 


else


 


printf("the given no is NOT Armstrong no.%d",e);


 


return 0;


}

nirosha

• Aug 17th, 2011

 

153 is the armstrong nummber

Code
#include<stdio.h>


void main()


{


     int n,sum=0,r;


     clrscr();


     printf("Enter your number");


     scanf("%d",&n);


     if(n>0)


     {


             r=n%10;


             sum=sum+r*r*r;


             n=n/10;


      }


      printf("%d",sum);


      getch();


}


 

Tanuja Jaiswal

• Jan 26th, 2012

 

Code
#include<stdio.h>


#include<conio.h>


void main()


{


int num,digit,sum=0;


printf("Enter any number ");


scanf("%d",&num);


while(num!=0)


{digit=num%10;


sum=sum+(digit*digit*digit);


num=num/10;


}


if(sum==num)


  printf("The number %d is armstrong",num);


else


  printf("The number %d is armstrong",num);


getch();


}