Find the number of Marbles

In A, B, C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A, B and C have equal number of marbles. (i) If x,y,z are the marbles initially with A,B,C respectively. Then
find the number of marbles B have at the end.

Questions by AtulSharma187

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step 1 a to
b=y
c=z
end a=x-(y+z)
      b=2y c=2z
step 2 B to
c=2z
a=x-(y+z)
end
a=2(x-y-z)
b=2y-(2z+x-y-z)=3y-z-x
c=4z
step 3  C to
a=2(x-y-z)
b=3y-z-x
now b has=2(3y-z-x)

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Md Parvez

  • Mar 16th, 2011
 

first a,b and c have same number of marbles.
a->x
b->y
c->z
now a gave b and c so
a->-x
b->y+y
c->z+z
now b gave a and c
a->-x+x
b->0
c->z+z+z
now c gave a and b
a->-x+x+x
b->0+y
c->z


it means a have x, b have y and s have z.same as they had initially.

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