A non stop bus to Amritsar overtakes an auto also moving towards Amritsar at 10 am. The bus reaches Amritsar at 12.30 pm and starts on the return journey after 1 hr. On the way back it meets the auto at 2 pm. At what time the auto will reach Amritsar?
Bus covers X distance in 5 steps of 0.5 hr on return journey met rick in 0.5 hr i.e. 1/5th the total distance, so rick has to travel 1/5th distance more. To cover 4/5th distance it took 4 hrs(2.5+1+0.5). So to cover remaining 1/5th it will now take 1 Hr
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Bus covers X distance in 5 steps of 0.5 hr on return journey met rick in 0.5 hr i.e. 1/5th the total distance, so rick has to travel 1/5th distance more. To cover 4/5th distance it took 4 hrs(2.5+1+0.5). So to cover remaining 1/5th it will now take 1 Hr
let the speed of the bus be x since it meets cycle at 10 and reaches destinantion at 12.30 distance from meeting point to destination is 2.5x
since cycle also moves it moves for 4 hourse (from 10-2) let its speed be y so cycle distance covered is 4y
when bus returns from destinaiton at 1.30 it just travels for .5hr (so .5x covered)
so 4y+.5x=2.5x total dis from meeting meeting point (1st meeting) to destination is 5y cycle has covered 4y in 4hrs so it will take i hour for the remaining y
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