Gerda Profile Answers by Gerda May 8th, 2008 One of possible solutions:public class NumberSpiralShape { /*** @param args*/public static void main(String[] args) { // TODO Auto-generated method stub int n = 3, i, side = n, x=0, y=0;int tab [][]= new int [n][n]; i=n*n;while(i>=1){for(int j=0; j<side; j++) tab[x][y++] = i--;x++;y--;if(i>=1){for(int j=0; j<side-1; j++) tab[x++][y] = i--;x--;y--;}if(i>=1){for(int j=0; j<side-1; j++) tab[x][y--] = i--;x--;y++;}if(i>=1){for(int j=0; j<side-2; j++) tab[x--][y] = i--;y++;x++;side=side-2;}}//printfor(i=0; i<n; i++){ for(int j=0; j<n; j++)System.out.print(tab[i][j] + " ");System.out.println("n"); }}}

datdo Profile Answers by datdo Jan 29th, 2009 //spiral//by datdo//translated C codepublic class Spiral {int n =3;public static int SPIRALHEIGHT = n;public static int SPIRALWIDTH = n;public static main(String[] args) { int matrix[SPIRALWIDTH][SPIRALHEIGHT]; int c,r,rr, cc; int a = 0; cc = 0; rr = 0; for(c = 0; c < SPIRALHEIGHT; c++) { for(r = 0; r < SPIRALWIDTH; r++) { matrix[r][c] = 0; } } c =-1; r =-2; while(a < SPIRALWIDTH * SPIRALHEIGHT) { for(r+=2; r < SPIRALWIDTH -rr; r++) { matrix[r][c+1] = a; a++; } for(c+=2; c < SPIRALHEIGHT - cc; c++) { matrix[r - 1][c] = a; a++; } cc++; for(r-=2; r > rr-1 ; r--) { matrix[r][c - 1] = a; a++; } for(c-=2; c > cc-1 ; c--) { matrix[r+1][c] = a; a++; } rr++; } for(c = 0; c < SPIRALHEIGHT; c++) { for(r = 0; r < SPIRALWIDTH; r++) { System.out.print("%3d ", matrix[r][c]); } System.out.print("n"); }}

## Printing numbers in spiral shape

Ex: if n=3, it should print like

9 8 7

2 1 6

3 4 5

Thanks in advance

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