Core Java - What will be the result and why

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Core Java | Question 468 of 493

What will be the result and why

int i=10;
i=i++;
System.out.println(i);

Total Answers and Comments: 14

Last Update: July 14, 2008 Asked by: Arnab.infinity

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Best Rated Answer

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Submitted by: fcasttro

10 Only. Since this is post increment Operator

Above answer was rated as good by the following members:
getravi2k, praspasr2

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March 19, 2008 07:02:39

swa_jag

Member Since: March 2008 Contribution: 1

RE: What will be the result and why

eleven

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March 21, 2008 08:18:39

fcasttro

Member Since: March 2007 Contribution: 16

RE: What will be the result and why

10 Only. Since this is post increment Operator

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1 1

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March 24, 2008 10:09:56

subbaraju.p

Member Since: March 2008 Contribution: 1

RE: What will be the result and why

eleven, as "i" will be updated before the system.out.print statement executes.

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April 01, 2008 04:01:27

poonamjava

Member Since: December 2006 Contribution: 20

RE: What will be the result and why

value of i will be 10

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April 01, 2008 04:17:29

poonamjava

Member Since: December 2006 Contribution: 20

RE: What will be the result and why

i will be 10

because i=i++;
if u break it
i=i; //1 step
here we are assigned the value and same variable.

if u r taking some other variable like j
j=i++

now print System.out.print(i+" "+j)
Ans:

i=11
j=10

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April 01, 2008 04:17:49

nadhem

Member Since: March 2008 Contribution: 1

RE: What will be the result and why

value will be 10,

the value is affected before being evaluated,

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April 16, 2008 05:01:11

kolli.Dedeepya

Member Since: April 2008 Contribution: 1

RE: What will be the result and why

10 because i will be first assigned and then incremented

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April 16, 2008 08:24:39

redleader

Member Since: April 2008 Contribution: 10

RE: What will be the result and why

In C++ and other languages the answer will be 11

Somehow it is 1=10. What should be noted is that i never gets incremented to 11.

int i=10;i=i++;System.out.println(i);

should not be logically different from

int i=10;
i=i;
i++;
System.out.println(i);

but in java somehow, it is logically different.

Post increment never occurs, or occurs but is discarded!!!!!!!!!!!!!!!!!!!!
This is a fundamental flaw in basic arithmatic in java!!!!!!!!!

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April 16, 2008 08:25:43

redleader

Member Since: April 2008 Contribution: 10

RE: What will be the result and why

on second line 1=10 should be i=10, for those who didnt know.

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May 02, 2008 02:46:49

#10

kishorpatil85

Member Since: April 2008 Contribution: 1

RE: What will be the result and why

i will be 10 bcoz of associativity it just ignores post increament operator,
but it will work for pre-increament

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