out is the object of printstream class... System.write() will write in byte stream fashion.. but System.out.println() will write in character stream format..

out is a object of System class.
It is used to display output on the console.

while using threads, each thread has access to object's instance variable. so while one thread is making changes to that instance variable, another thread may access it. It results in inconsistenc...

i think there is no possibility of creating user defined unchecked exceptions.

Unchecked exceptions are those which extend RunTimeException? what do you mean by userdefined unchecked exceptions? Unchecked exceptions are thrown only at run time. The question is ambiguous.

final keyword can be applied on:- 1.class 2.member functions(only non-static) 3.data-members(both static and non-static) 4.local variables. 1.by making a class final ,that class cannot be inherited....

Like any variable, a final variable can also be first declared and then assigned a value. But it can be only assigned a value once and only once ( as its final variable ). for example :- final Strin...

if the object has been created to the subclass and both the methods are non static then the method we overriden doesnt produce any errors or exceptions.

throws exception in super class doesnt affest over-riding:code eg as follows: "java public class Ride{ void clay(){ System.out.println("am in base class"); } public static voi...

Static data members field (variable) and method belong to class. Static fields can be used before creating an instance of the class and static method can be accessed using class name.

Static data member has a class scope. A single copy of static data member get shared within the objects of that class. A non-static member cannot access a static member of that class.

Output is "catching exception"

This will give error that exception caught already

11, because even it is post increment, it will increment by 1 when it is going to reach println() statment, for the first statement(i++;) it wont increment, after completing the execution of this method i incremented by 1 and prints the result.

Yes this is similar to
temp = i;
i = i+1;
i = temp;
It will restore the value 10 since post increment. If its pre-increment last assignment will be i = temp+1

java refers to basic concept of java as well as new technical features making foundation of java/j2ee.
j2ee is used for enteprise application based on java concept.
if java is foundation then j2ee is building for business purpose. 

java refers to core java and j2ee refers to the technologies that are developed using java. for example inheritance, exception handling, multithreading are some of the concepts in java and servlets, R...

It is an object oriented feature which provides the reusablity of code. All the properties defined in the parent class can be used by its child classes without writing the code again.

All Common features are come to parent class. So we can extend this class to child classes. Child classes contais some special features.

Useage of inheritance : it reduce the code. If we use inheritance, we avoid redundent code.

class StringConver{ public static void main(String[] s) {     //String s1 = "Hello"; If you try this you will get NumberFormatException     ...

if u try to convert "hello" to int u will get NumberFormatException

Java Does not Support Pass by Reference

Java does not support pass by reference. Java actually pass-by-value for all variables running within a single VM. pass-by-value means pass-by-variable-value and that means pass-by-copy-of the variabl...

It will compile but gives error at run time......

The complier will throw error that there is no main()  method. main() should be public always please note.

String s="10";
int a= Integer.parseInt(s);  //Integer.parseInt() method is used to convert str to int

String a='5';
int i;
i=int(a);

The answer is 2, because  the statement
i = (++i) / (i++)

will be processed from left to right
i = (++10) / (10++)

which means

i = 11/10++

Here still ++ operator is not executed

i = 1++; // 1 because it is an integer operation
i = 2;

if you change
i = (++i) / (++i) you will see 1

chethan is write

sub class

super class

Ans is (d) None of the above

Because we are not defining else part of the if statement.

Unreachable code error because of the absence of else part.

D)None of the above

Yes objects can be created only using constructors if we do not provide one compiler will create a default cons for us thus allocating memory for objects we are going to create and the default values ...

Yes, Constructors only initializes the object.

true

False

When we read e-mail, we are viewing passive data.

Passive

int type is the parameter of sleep() method.

long is the correct answer.

all three answers above are correct. in 3rd one we are assigning object of B to reference of B itself. But in first and second answers we are assigning object of B to Reference of A. In all three cases JVM will invoke B's display() only.

abstract class A {     void display()     {     } }class B extends A {     void display()     {   &n...

Yes I tested this we can have main method in two different classes this will not give error and we should save that doc with the class name which has the main we want to be executed first and inside t...

yes this is possible...... but within a single file only one class can be declared puiblic!!!!
and whichever class you run, that class's main() mentod would be called.......

vinny

Both behave the same way except that when we import in java we can import single class also but we have to include a file and not a Class in C++.eg: import java.lang      ...

by using include preprocessor kn c++  the program size will be slightly increased but when we use import statement in java the program size will not be increased at all

exception object can be caught only once after it was caught i think it will be eligible for garbage collection. Not that it will be immediately destroyed but it will be destroyed soon if we are not using that object to detect what kind of exception it is.

BufferedWriter obj=new BufferedWriter(new FileWriter(new File("test.txt")));obj.write("hai");    //after this without using flush if u close obj "hai" will...

flush();