Code
int i, j, k;
char a[] = { 'A', 'B', 'C', 'D', 'E', 'F', 'G' };
for (i = 0; i < 7; i++) {
for (k = 0; k < 7 - i; k++)
for (j = 7 - (i + 1); j >= 0; j--)
}
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Code
#include<conio.h>
#include<stdio.h>
#include<string.h>
void main()
{
char arr[]="ABCDEFG";
int i,j,length=strlen(arr);
clrscr();
while(length>0)
{
for(i
=0;i
<length
;i
++) printf(" %c",arr
[i
]);
for(j
=length
-2;j
>=0;j
--) printf(" %c",arr
[j
]);
length--;
}
getch();
}
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Code
#include<stdio.h>
int main()
{
/*This code is for any input upto 'Z' from 'A' */
char i, j, k;
int a;
scanf(" %c", &j);
for (a = j; a <= j; a++) {
for (i = 'A'; i <= a; i++)
for (k = a - 1; k >= 'A'; k--)
}
for (a = j - 1; a >= 65; a--) {
for (i = 'A'; i <= a; i++)
for (k = a; k >= 'A'; k--)
}
return 0;
}

1 User has rated as useful.
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GNANAPRAKASH.S
Answered On : Aug 9th, 2011
Code
#include<stdio.h>
#include<conio.h>
void main()
{
int i, j, k, n;
char a[30];
clrscr();
scanf
("%d", &n
, printf("Enter the number of lines upto alpahbets:"));
for (i = n; i >= 1; i--) {
for (j = 1; j <= i; j++) {
a[j] = 64 + j;
}
for (k = j - 1; k >= 1; k--) {
}
");
}
getch();
}
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Code
#include
#include
using namespace std;
int main()
{
char a[] = "abcdefg";
char b[] = "fedcba";
m = strlen(a);
n = strlen(b);
for (int i
= 0; i
cout < cout << int k
= 1; while (m
> 1 && k
{
int l
= 0; for (int i
= 0; i
cout < for (int i
= k
; i
cout < cout < m
--; k
++;
}
cin >> z; return 0;
}
<<<
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This one works
Code
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
char a[] = "abcdefg";
char b[] = "fedcba";
cout << a << b << endl;
int m, n;
m = strlen(a);
n = strlen(b);
for (int i = 0; i < m - 1; i++)
cout << a[i];
cout << b << endl;
int k = 1;
while (m > 1 && k < n)
{
int l = 0;
for (int i = 0; i < m - 2; i++)
cout << a[i];
for (int i = k; i < n; i++)
cout << b[i];
cout << endl;
m--;
k++;
}
return 0;
}
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Anil
Answered On : Oct 7th, 2011
Code
#include<stdio.h>
#include<conoio.h>
void main()
{
int len, i, j, k;
char a[] = { 'A', 'B', 'C', 'D', 'E', 'F', 'G' };
clrscr();
len = a.count();
for (i = 0; i < len; i++) {
for (j = 0; j < len - i; j++) {
}
for (k = ((len - 2) - i); k >= 0; k--) {
}
");
}
getch();
}
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Gaurav Bhadauria
Answered On : Oct 13th, 2011
Code
int i, j, k;
char a[] = { 'A', 'B', 'C', 'D', 'E', 'F', 'G' };
for (i = 0; i < 7; i++) {
for (k = 0; k < 7 - i; k++)
for (j = 7 - (i + 1); j >= 0; j--)
}
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Jimmy Jack
Answered On : Apr 25th, 2012
Code
#include <iostream>
#include <fstream>
void display_sequence2(int depth)
{
int output_count = 0;
for (int count = depth - 1; count >= 0; --count) {
for (int index = 0; index <= count; ++index)
std
::cout << (char) ((((output_count
++ == 0) || (index
== 2)) ? A
: a
) + index
) << " ";
for (int index = (count == (depth - 1)) ? count - 1 : count; index >= 0; --index) {
std
::cout << (char) ((((output_count
++ == 0) || (index
== 2)) ? A
: a
) + index
);
if (index > 0)
}
}
}
int main()
{
display_sequence2(7);
}
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