Usman Adil Profile Answers by Usman Adil Questions by Usman Adil Jan 31st, 2009 It should be noted that when springs are in series then their equivalent stiffeness decreases and when they r in parallel, stiffness increases.so we have to apply a larger force in parallel spring system and lower force in series system.
kumarrajesh18587 Profile Answers by kumarrajesh18587 May 16th, 2012 1.All Springs in series will experience the same force F applied at the end. (F=F1=F2)2.Total deflection of this system will be equal to deflection of individual spring (L=L1+L2)As F=KL THEREFORE F1=K1 x L1 , F2=K2 x L2 OR L1=F/K1, L2=F/K2 SO L=L1+L2 WILL BECOME F/K=F/K1+F/K2 OR 1/K=1/K1+1/K2 OR K=(K1 x K2)/(K1+K2)
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