Stiffness

If two springs of stiffness K1 & K2 are in series, the equivalent stiffness is.......................

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nk

  • Aug 5th, 2011
 

1/k1+1/k2

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kumarrajesh18587

  • May 16th, 2012
 

1.All Springs in series will experience the same force F applied at the end. (F=F1=F2)

2.Total deflection of this system will be equal to deflection of individual spring (L=L1+L2)

As F=KL

THEREFORE

F1=K1 x L1 , F2=K2 x L2
OR L1=F/K1, L2=F/K2
SO L=L1+L2 WILL BECOME
F/K=F/K1+F/K2
OR 1/K=1/K1+1/K2
OR K=(K1 x K2)/(K1+K2)

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MECHANICAL

  • Nov 21st, 2017
 

K1+K2

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deepak kumar

  • Mar 7th, 2018
 

k1k2/(k1+k2)

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