Two numbers are entered through keyboard, write a program to find the value of one number raised to the power another.

Code
 
 
#include
#include
main()
{
int a,b,c;
clrscr();
printf("enter two no.:");
scanf("%d%d",&a,&b);
c=a+b;
pritf("sum of no.is=%d",c);
getch();
}
 

Code
#include
#include
#include
void main()
{
int a,b;
printf("enter the 2 nos:");
scanf("%d",&a,&b);
pow(a,b);
getch();
)
pow(a,b0
{
return(a^b);
}

Code
#include
int main()
{
int a,b,i,prod=1;
printf("Enter a number :");
scanf("%d",&a);
printf("Enter its power:");
scanf("%d",&b);
for(i=0;iprod = prod*a;
printf("pow(a,b) = %d", prod);
getch();
return 0;
}

Code
main() 
{
        scanf("%d",&a); // base
         scanf("%d",&b); //power
         for(int i=0;i             a=a*b;
        printf("result is..%d",a);
}

Code
#include<conio.h>
#include<stdio.h>
#include<math.h>
main()
{
    int a,b,num,i;
    printf("enter the number ");
    scanf("%d",&a);
    printf("enter the number  in power");
    scanf("%d" , &b);
  num = pow(a,b);
  
   printf("%d" , num);
    getch();
}

Code
#include<stdio.h>
#include<iostream>
using namespace std; 
/* Function to calculate x raised to the power y */
float power(int x,  int y)
{
 float pow=1.0;
int temp=y;
if((temp>>31)==-1) temp=-1*temp;
if(temp==1 && (y>>31)==-1) return (1.0/x);
else if(temp==1 && !(y>>31)) return x;
   while(temp>0){
 
        if(y>0){
        if((temp&1)==0)
        pow*=x*x;
        else pow*=x*x*x;
        }
        else pow=(pow/(x*x));
        temp=temp/2;
   }
return pow;
 
}
 
/* Program to test function power */
int main()
{
    int x = 
     int y = 2;
 
    printf("%f", power(x, y));
    getchar();
    return 0;
}

How to work the scanf function?

It traverse the char type format specifier from left to right and assign the value from stdin to the address of the variable. Scanf return type is int and return the number of argument.


Its syantax is scanf(const char *,...), there is the ... represent the variable argument list.