When you reverse the digit of age of father you will get the age of the son. One years ago the age of father was twice that of son's age. What are the current ages of father and son?

First option is the answer of this question i.e. 73 and 37

The answer is 73 & 37..
 

first option 37 and 73
let current age of son is x and age of father is y
then one year ago
x-1,y-1
also according to given condition
2(x-1)=y-1
2x-y=1
above eqaution holds good for 37 and 73

1st option is right 73 & 37.

father=73, son=37,
 one year ago................ father=72, son=36, so father=2* son

The option is 73 and 37 is correct because 1 year ago,
son's age: 36
father's age: 72 i.e. twice the age of son's age.

When u reverse the digits of age of father u will get the age of son.
10x + y = fathers age
10y + x = sons age
:
one year ago the age of father was twice that of sons age.
10x + y - 1 = 2(10y + x - 1)
10x + y - 1 = 20y + 2x - 2
10x - 2x = 20y - y - 2 + 1


8x = 19y - 1
x = y -
Only one set of single digit integers will satisfy this equation
y = 3; x = 7
:
what are the current ages of father and son?
Dad is 73, son is 37
: