C - What will be the output of the code?#includemain(){int a=10;int b;b=a++ + 20;printf("a= %d b= %d", a

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What will be the output of the code?

#include
main()
{
int a=10;
int b;
b=a++ + 20;
printf("a= %d b= %d", a, b);
}

The o/p will be 11 30. Can somebody tell me how?

Total Answers and Comments: 3

Last Update: July 02, 2008 Asked by: vrijesh28

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Best Rated Answer

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Submitted by: Dan Dancescu

The output is 11 30, because "++" is a postfix operator (applied after the operation) so the value that gets assigned to b is the initial value of a, which is 10, plus 20.

So b will be 30. Then a is incremented by 1, so a becomes 11.

Therefore this program prints out 11 30

Above answer was rated as good by the following members:
rajani_vaddepalli15

October 09, 2007 22:45:26

Dan Dancescu

RE: What will be the output of the code?#i...

The output is 11 30 because "++" is a postfix operator (applied after the operation) so the value that gets assigned to b is the initial value of a which is 10 plus 20.

So b will be 30. Then a is incremented by 1 so a becomes 11.

Therefore this program prints out 11 30

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1 0

Overall Rating: +1

November 07, 2007 01:17:25

amma_mans80

Member Since: November 2007 Contribution: 1

RE: What will be the output of the code?#i...

a 11 b 30

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July 02, 2008 04:51:22

jintojos

Member Since: May 2008 Contribution: 29

RE: What will be the output of the code?#includemain(){int a=10;int b;b=a++ + 20;printf("a= %d b= %d", a, b);}

The variable a is incremented by one only after completing
the statement b a++ + 20;
So after executing the statement b a++ + 20 the variable b will have the value 30.
Then the value of variable a is incremented that is why the out put is 11 30.

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