What will be result of the following program?void myalloc(char *x, int n){x= (char *)malloc(n*sizeof(char));memset(x,,n*sizeof(char));}main(){char *g="String";myalloc(g,20);strcpy(g,"Oldstring");printf("The string is %s",g);}a) The string is : Stringb) Run time error/Core dumpc) The string is : Oldstringd) Syntax error during compilatione) None of these

  • Interview Candidate
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  • 2022

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Zhang Long

  • Nov 23rd, 2007
 

the answer B is right, cause g is a pointer to a constant string, so the function strcpy will fail.

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