The average length of three tapes is 6800 feet. None of the tapes is less than 6400 feet. What is the greatest possible length of one of the other tapes?

7600

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DIPAYAN DUTTA CHOWDHURY

  • Oct 11th, 2006
 

AS THE MINIMUM LENGTH IS 6400,

THE 2 TAPES CAN BE OF LENGTH 6400,

SO THE NEXT ONE WILL BE MAX= (6800*3)-(2*6400)=7600

Gowtham

  • Feb 9th, 2018
 

Let 3 ropes be x,y and z
given (x+y+z)/3 =6800
so 2 ropes must be 6400 each (minimum)
(6400+6400+z)/3=6800
which gives z=7600

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muthukrishnan

  • Jun 2nd, 2019
 

x+y+z
----- = 6800
3
x>=6400
6400 + y + z = 20400
y + z = 14000
to get the greatest of y and z, lets assume y = 6400
so, z = 7600
so ANS is 7600

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