If log(3.14) and log(3.16) are given, What is the value of log(3.15)?

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jigar

  • Sep 23rd, 2007
 

log(3.14)+log(3.16)/2

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Let  log(3.14)=a;
       3.15=10^a;
       log(3.16)=b;
       3.16=10^b ;

      3.15=(3.14+3.16)/2

     3.15=(10^a+10^b)/2

     log=log(10^a+10^b) - log2 

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Let  log(3.14)=a;
       3.15=10^a;
       log(3.16)=b;
       3.16=10^b ;

      3.15=(3.14+3.16)/2

     3.15=(10^a+10^b)/2

     log(3.15)=log(10^a+10^b) - log2 

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log(3.15) = log(3.14 + 0.01)

log(3.15) = log(3.16 - 0.01)

log(3.15)* log(3.15)= log(3.14) * log(0.01) * log (3.16) / log(0.01)

log(3.15)* log(3.15)= log(3.14) * log (3.16)

2 * log(3.15)= (log(3.14) * log (3.16) )

log(3.15)= (log(3.14) * log (3.16) )/2

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