4 thieves rob a bakery of the bread one after the other. Each thief takes half of what is present & half a bread. If at the end 3 bread remains, what is the number of bread that was present initially?

Definitely the ans is 63 because: last time the bread left is 3 now we know that this comes when 4th theif took half of the remaining bread left by 3rd and 1/2 more, so reverse the process, add 12 to 3 that makes 72. and then multiply by 2. this will be 7 so 7 will be left by 3rd thief , now again reverse. 2(7+12) = 15 . do this 2 more times and the ans will come as 63 for last time,

NOTE: THis will be the minimum breads present originals

The correct answer is 52. Let x is the no. of initially breads present. then x-(x+1)/2-(x+3)/4-(x+7)/8-(x+15)/16= 3 Hence x 52

uma

Jan 4th, 2015

a woman goes to company 6 days in aweek the bus fare for her 1 day journey is 0.2$,and on every saturday she uses her car to go to office and the expenditure is 3$ how much will be rise of her total expenditure for a week if she uses car to go

## 4 thieves rob a bakery of the bread one after the other. Each thief takes half of what is present & half a bread. If at the end 3 bread remains, what is the number of bread that was present initially?

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