# 4 thieves rob a bakery of the bread one after the other. Each thief takes half of what is present & half a bread. If at the end 3 bread remains, what is the number of bread that was present initially?

#### nmodi

• Jul 17th, 2005

Ans. 48

#### sachin kumar rai

• Aug 6th, 2005

according to my calc. the no. of breads = 64

#### ashish g

• Oct 20th, 2005

#### ashish g Profile Answers by ashish g

• Oct 20th, 2005

#### Sheetal Salunkhe

• Nov 21st, 2005

initially the breads should be 48. first thief took 24  of 48 second one took 12 of 24 third one have took 6 of 12 then remains 3 breads.

#### sunita

• Dec 20th, 2005

ans:

it will be 63

procedure:

let initially der are x breads

1st thief takes=x/2 +1/2   ,so remaining=x-(x/2+1/2)=x/2-1/2

2nd thief takes=1/2+1/2*(x/2-1/2)=1/2+x/4-1/4=x/4+1/4 so remain=x/2-1/2-x/4-1/4=x/4-3/4

3rd thief takes=1/2 +1/2*(x/4-3/4)=1/2+x/8-3/8=x/8+1/8 so remain=x/4-3/4-x/8-1/8=x/8-7/8

4th thief takes=1/2+1/2*(x/8-7/8)=1/2+x/16-7/16=x/16+1/16 so remain=x/8-7/8-x/16-1/16=x/16-15/16

so x/16-15/16=3

x=48+15=63(ans)

#### jaspreet(jagz)

• Feb 19th, 2006

63( ( ( ( X/2-B/2 )/2 -B/2 )/2 -B/2 ) /2 -B/2 ) =3B=>( X-15B) /16 =3B==>X=63B

• Jun 20th, 2006

Let the no. of breads initially present be x.Then1 st thief takes x/22 nd thief takes x/43 rd thief takes x/84th thief takes x/16.Remaining = 3 breadsEquating x/2 + x/4 + x/8 + x/16 + 3 = x(15x + 48)/16 = x15x + 48 = 16x=> x = 48The number of breads initially present were 48.

#### amateur

• Aug 7th, 2006

Ans : 48

Let Total no of breads be X.

=> 1st Thief took X/2 remaining X/2

=> 2nd Thief took 1/2 * X/2 = X/4 remaining X/2-X/4= X/4

=> 3rd Thief took 1/2 * X/4 = X/8 remaining X/4-X/8=X/8

=> 4th Thief took 1/2 * X/8 = X/16 remaining X/8-X/16=X/16

Now its given that remaining bread = 3

Therefore X/16=3

=> X = 48

Ans = 48.

#### maximus

• Oct 25th, 2006

63

#### Pooja

• Dec 1st, 2006

#### Jekin

• Jun 30th, 2007

should be 63. the ones who think it's 48 didn't take half bread into consideration.

#### puspanjali

• Aug 27th, 2007

if the  total no of bread is=x

then the first thieves is stolen           :(x/2+1/2)

2nd thieves is stolen half of the

3rd                                                       :(1/2(1/2(x/2+1/2)+1/2)+1/2)

4th                                                        :(1/2(1/2(1/2(x/2+1/2)+1/2)+1/2)+1/2)

which is => 3(the remaining bread)=(1/2(1/2(1/2(x/2+1/2)+1/2)+1/2)+1/2)

=> x=36

#### mohdriz_ibm Profile Answers by mohdriz_ibm

• Jul 21st, 2008

third one took 6,
second one took 12,
first one took 24 i.e. Half of the total breads

#### annancy Profile Answers by annancy

• Mar 28th, 2009

total=x
x=x/2+x/4+x/8+x/16+3
x=(15x+48)/16
x=48

#### jasdeep1111 Profile Answers by jasdeep1111

• Jul 24th, 2009

Definitely the ans is 63 because:
last time the bread left is 3 now we know that this comes when 4th theif took half of the remaining bread left by 3rd and 1/2 more, so reverse the process, add 12 to 3 that makes 72. and then multiply by 2. this will be 7 so 7 will be left by 3rd thief , now again reverse. 2(7+12) = 15 . do this 2 more times and the ans will come as 63 for last time,

NOTE: THis will be the minimum breads present originals

#### keesh Profile Answers by keesh

• Oct 26th, 2009

Am sorry to say, none of you read the question fully,

"The thieves took half of what is present and also HALF A BREAD"

= 48 + 2
= 50

correct me if i am wrong.

#### itclanster Profile Answers by itclanster

• Dec 12th, 2009

Let x is the no. of initially breads present.
then
x-(x+1)/2-(x+3)/4-(x+7)/8-(x+15)/8=3
Hence x=52

#### itclanster Profile Answers by itclanster

• Dec 12th, 2009

Let x is the no. of initially breads present.
then
x-(x+1)/2-(x+3)/4-(x+7)/8-(x+15)/16= 3
Hence x 52

#### uma

• Jan 4th, 2015

a woman goes to company 6 days in aweek the bus fare for her 1 day journey is 0.2\$,and on every saturday she uses her car to go to office and the expenditure is 3\$ how much will be rise of her total expenditure for a week if she uses car to go

#### sandeep roy

• Jan 6th, 2015

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