i_upal Profile Answers by i_upal Sep 23rd, 2007 My age : 10x+y Son age : 10y+xso 10x+y = 10y+x 10x+y-1 = 2(10y+x-1) x = (19y-1)/8 for y=3 (19y-1) is completely divisible by 8 so x = 7So my present age : 10*7+3 = 73 son's age : 10*3+7 = 37

naveenkumar17 Profile Answers by naveenkumar17 Feb 19th, 2009 My age : 10x+y Son age : 10y+x So 10x+y = 10y+x 10x+y-1 = 2(10y+x-1) x = (19y-1)/8 For y=3 (19y-1) is completely divisible by 8 So x = 7 So my present age : 10*7+3 = 73 Son's age : 10*3+7 = 37

milan.kadivar Profile Answers by milan.kadivar Feb 20th, 2009 My age : 10x+y Son age : 10y+xso 10x+y = 10y+x 10x+y-1 = 2(10y+x-1) x = (19y-1)/8for y=3 (19y-1) is divisible by 8Therefore x = 7So my present age : 10*7+3 = 73 son's age : 10*3+7 = 37

## If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

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i_upalProfile Answers by i_upal Questions by i_upal

My age : 10x+y

Son age : 10y+x

so 10x+y = 10y+x

10x+y-1 = 2(10y+x-1)

x = (19y-1)/8

for y=3

(19y-1) is completely divisible by 8

so x = 7

So my present age : 10*7+3 = 73

son's age : 10*3+7 = 37

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