# If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

i_upal Profile Answers by i_upal Questions by i_upal

• Member Since Apr-2007 | Sep 23rd, 2007

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
10x+y-1 = 2(10y+x-1)
x = (19y-1)/8

for y=3
(19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
son's age  :  10*3+7 = 37

#### i_upal Profile Answers by i_upal

• Sep 23rd, 2007

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
10x+y-1 = 2(10y+x-1)
x = (19y-1)/8

for y=3
(19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
son's age  :  10*3+7 = 37

#### naveenkumar17 Profile Answers by naveenkumar17

• Feb 19th, 2009

My age : 10x+y
Son age : 10y+x
So 10x+y = 10y+x
10x+y-1 = 2(10y+x-1)
x = (19y-1)/8
For y=3 (19y-1) is completely divisible by 8
So x = 7
So my present age : 10*7+3 = 73
Son's age : 10*3+7 = 37

#### veeru21 Profile Answers by veeru21

• Feb 19th, 2009

73 if we reverse it is 37
one year ago 36*2 = 72

#### milan.kadivar Profile Answers by milan.kadivar

• Feb 20th, 2009

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
10x+y-1 = 2(10y+x-1)
x = (19y-1)/8

for y=3
(19y-1) is  divisible by 8

Therefore x = 7

So my present age : 10*7+3 = 73
son's age  :  10*3+7 = 37

#### ammy

• Sep 11th, 2016

Why you took y=3 ..n? What is the reason behind its divisibility by 8?

#### Ahamika

• Jan 7th, 2017

Why should we take y as 3? Can it be solved without assumption?  