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If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

Asked by: Interview Candidate | Asked on: Jun 14th, 2007

Editorial / Best Answer

Answered by: i_upal

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Member Since Apr-2007 | Answered On : Sep 23rd, 2007

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3    
           (19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37 

Showing Answers 1 - 4 of 4 Answers
i_upal

Answered On : Sep 23rd, 2007

View all answers by i_upal

My age : 10x+y Son age : 10y+xso 10x+y = 10y+x     10x+y-1 = 2(10y+x-1)     x = (19y-1)/8 for y=3               (19y-1) is completely divisible by 8 so x = 7So my present age : 10*7+3 = 73             son's age  :  10*3+7 = 37 

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naveenkumar17

Answered On : Feb 19th, 2009

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My age : 10x+y
Son age : 10y+x
So 10x+y = 10y+x
10x+y-1 = 2(10y+x-1)
x = (19y-1)/8
For y=3 (19y-1) is completely divisible by 8
So x = 7
So my present age : 10*7+3 = 73
Son's age : 10*3+7 = 37

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veeru21

Answered On : Feb 19th, 2009

View all answers by veeru21

73 if we reverse it is 37one year ago 36*2 = 72

  
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milan.kadivar

Answered On : Feb 20th, 2009

View all answers by milan.kadivar

My age : 10x+y Son age : 10y+xso 10x+y = 10y+x     10x+y-1 = 2(10y+x-1)     x = (19y-1)/8for y=3               (19y-1) is  divisible by 8Therefore x = 7So my present age : 10*7+3 = 73             son's age  :  10*3+7 = 37 

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