Aptitude - If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was t

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If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

Total Answers and Comments: 4

Last Update: February 20, 2009 Asked by: sujatha

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Best Rated Answer

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Submitted by: i_upal

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3
           (19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37

Above answer was rated as good by the following members:
rockingroshan, mandy5229, jayagopal, skcet, deepak643

September 23, 2007 10:42:22

i_upal

Member Since: April 2007 Contribution: 1

RE: If the digits of my present age are reversed then ...

My age : 10x+y
Son age : 10y+x

so 10x+y 10y+x
10x+y-1 2(10y+x-1)
x (19y-1)/8

for y 3
(19y-1) is completely divisible by 8
so x 7

So my present age : 10*7+3 73
son's age : 10*3+7 37

Is this answer useful? Yes | No

5 0

Overall Rating: +5

February 19, 2009 08:28:56

naveenkumar17

Member Since: February 2009 Contribution: 2

RE: If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

My age : 10x+y

Son age : 10y+x

So 10x+y 10y+x

10x+y-1 2(10y+x-1)

x (19y-1)/8

For y 3 (19y-1) is completely divisible by 8

So x 7

So my present age : 10*7+3 73

Son's age : 10*3+7 37

Is this answer useful? Yes | No

February 19, 2009 23:19:36

veeru21

Member Since: February 2009 Contribution: 2

RE: If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

73 if we reverse it is 37
one year ago 36*2 72

Is this answer useful? Yes | No

February 20, 2009 00:45:12

milan.kadivar

Member Since: February 2009 Contribution: 4

RE: If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

My age : 10x+y
Son age : 10y+x

so 10x+y 10y+x
10x+y-1 2(10y+x-1)
x (19y-1)/8

for y 3
(19y-1) is divisible by 8

Therefore x 7

So my present age : 10*7+3 73
son's age : 10*3+7 37

Is this answer useful? Yes | No

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