If the digits of my present age are reversed then i get the age of my son.If 1 year ago my age was twice as that of my son.Find my present age

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i_upal  

  • Member Since Apr-2007 | Sep 23rd, 2007


My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3    
           (19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37 

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i_upal

  • Sep 23rd, 2007
 

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3    
           (19y-1) is completely divisible by 8
so x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37 

My age : 10x+y
Son age : 10y+x

so 10x+y = 10y+x
     10x+y-1 = 2(10y+x-1)
     x = (19y-1)/8

for y=3    
           (19y-1) is  divisible by 8

Therefore x = 7

So my present age : 10*7+3 = 73
             son's age  :  10*3+7 = 37 

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