udaikiran

• Jul 20th, 2006

 

3.g - grass at the beginning r - rate at which grass grows, per day y - rate at which one cow eats grass, per day n - no of cows to eat the grass in 96 days g + 40*r = 40 * 40 * y------- 1 g + 60*r = 30 * 60 * y------- 2 g + n*r = 20 * n * y-------- 3 from 1 and 2 r=10y g=120r from 3 nr=120r Solving, n = 120

srinivasan

• Jul 31st, 2006

 

On the absence of 10 cows,the days the cows grazing the pasture increases by 20 days.Hence it must take 80 DAYS to graze for 20 cows.

Sneha

• Aug 8th, 2006

 

kindly solve me this puzzle and tell metha answer.......

there r two diffrent replies given here...which 1 is coreect?..

kindly tell me the right approach

ashokkumarnimmala

 Profile Answers by ashokkumarnimmala 

• Jul 27th, 2008

 

Inverse relationship exists between cows and graze
take a relation like  y=(m/x)+c;
where y=cows,x=graze
solve for m,c
 then substitute given cows in y and find out x
which comes to be 120

Mobasshir Anwar

• Mar 28th, 2017

 

40 cows in 40 days means =1600 work
30 cows in 60 days means =1800 work
Means 200 extra work in 20 days gets added, grass increases because of increasing day at the rate of 10 unit per day
It means before 40 days the grass must be = 1600- 40*10=1200 .... So in 20 days 20*10+1200=1400 grass by 20 cows @1400/20=70 Cows is the answer.