stranger1

 Profile Answers by stranger1 

• Sep 28th, 2007

 

Enumerate.... correct me if i am wrong....

Nagappan

 Profile Answers by Nagappan 

• Nov 13th, 2007

 

range is the built-in function to be used for interating the sequence of numbers.

for iter in range (0, 10):
   print iter # prints 0 to 9


for iter in range (0, 10, 2): # The last argument is the sequence to use. Default is 1.
   print iter # prints 0, 2, 4, 6, 8

addy

• Oct 15th, 2012

 

Yup, I think youre right. enumerate will iterate over a list, and that list could have numbers in it e.g.:

>>> [ (i,j) for i,j in enumerate([9,10,11,12])]
[(0, 9), (1, 10), (2, 11), (3, 12)]

Paulo Kuong

• Jun 10th, 2015

 

__next__ and __iter__

Tushar Gupta

• Aug 9th, 2015

 

You can use iter to iterate through a list of integers as

Code
a = iter(list(range(10)))


for i in a:


    print(i)

suchitra

• Oct 5th, 2015

 

Code
a = iter(range(4))


for i in a:


 print i

Rupali

• Jan 24th, 2016

 

range()

sethuraman

• Feb 5th, 2016

 

Using for loop is best one
Exp:
for i in range (start , end)
works fine

saravanan

• Mar 16th, 2016

 

a = iter(range(10))
a.next()

alok

• Apr 25th, 2016

 

class Counter:
def __init__(self, low, high):
self.current = low
self.high = high
def __iter__(self):
return self
def next(self): # Python 3: def __next__(self)
if self.current > self.high:
raise StopIteration
else:
self.current += 1
return self.current - 1
for c in Counter(3, 8):
print c

madan

• Jun 26th, 2017

 

range()
for i in range(10):
print i

Prem M S

• Aug 17th, 2017

 

syntax : range(start,end,step count)
Ex:
a = range(1,10,2)
print a
o/p:
[1, 3, 5, 7, 9]
If using to iterate
for i in range(1,10):
print i
o/p:
1
2
3
4
5
6
7
8
9