sharmila

• Nov 28th, 2006

 

#include<stdlib.h>

main()

{

int a=rand();

printf("%d",a);

}

siriatwork

 Profile Answers by siriatwork 

• Dec 9th, 2006

 

I think the above code would generate a random number based on the lower and higher limits defined in the compiler, but not from a "given List". if we want to generate randomly from a list then may be we can store the list of numbers in an array and then generate the index randomly and return the particular number...

arunsriniv23

 Profile Answers by arunsriniv23 

• Jun 20th, 2007

 

This prg generates a random no between the range specified in the compiler. If we want to generate a random no from a list, we can do it using array subscript. If we know the no of elements in the list, we can use % to generate a random subscript value between the specified limits. Hence using this we can select a random no from the list.

Eg.
Suppose there r 10 elements
Then,
subscipt=rand()%10 will give the required result

Now a[subscript] would be a random no from the array a.

NitinMishra

• Nov 5th, 2007

 

#include

main()

{

int a=rand();

printf("%d",a);

}

The above program creates random number but this program can better be modified by using seed() function i.e combination of rand() and seed().
The number generated by the above program is not random it follows the processor instruction all the time, so the output of the above program is not really random.

amitprasad

 Profile Answers by amitprasad 

• Mar 21st, 2008

 

NitinMishra is absoulutely right that number generated by rand() is not random. I think this code will serve the purpose.....

#include <stdio.h>
#include <time.h>

int main()
{
    // Just for example, i have taken the list
    int list[10] = {12, 34, 45, 19, 54, 78, 9, 10, 99, 77};
    int random = 0;
    srand ((unsigned int)time ((time_t *)NULL));
    random = rand()% 10;
    printf ("nRandom Number(index) = %d ::NUMBER = %dn", random, list[random]);
    return 1;
}