Which of the following is power of 3 a) 2345 b) 9875 c) 6504 d) 9833

Tell me the method to solve this....... plz
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t venkatesan

  • Oct 7th, 2006

model aps off camp anna univ ques papers

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  • Oct 8th, 2006


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  • Oct 8th, 2006

yes what mrsms deepa is given is right....

the method is divid the number by 3 if there is no remainder then it is the result...

even more simple way is to sum up the digit and if the sum is divisible by 3 then it is the answer....

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  • Oct 22nd, 2006

 hai  to everybody  to solve 

the  power of the 3 is so simply

like (sum of the given is divide by 3 is the first step

and find options only one one is correct)


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  • Feb 3rd, 2007

sorry guys i think all are wrongans is 9833because when we find the powers of 3i.e 3^1=3 ,3^2=9, 3^3=27 , 3^4=81 ,3^5= 243if u look at the unit places of the no can be only 3,9,7,1 and then the same sequence again continue...so the unit place with 3or9or7or1 in the options is 9833if u think its wrong open calculator and keep dividing with 3 all the options .this is the right one..

ujjal saha

  • Feb 6th, 2007

It is not possible all the time, that is, A No. is divided by three is a power of three.

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Ganesh babu

  • Feb 12th, 2007

you are correct.Power of 3 is nothing but n^35^3 = 125 which is not divisible by 3

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sankar reddy

  • Feb 20th, 2007

what girish said is absolutely correct

 3 power 1=3
3 power 2 = 9
3 power 3= 27
3 power 4=81
3 power 5=243........ so the last digits divisible by 3 are 3,9,7,1.
So the answer is 9833.

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  • Mar 1st, 2007

Dear friend, Correct ans is C - 6504, Simply you can add the digit of any no and then divide the sum with 3 only in the given option c satisfied the condtions.

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  • Mar 7th, 2007


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All the powers of 3 (except 3) viz., 9,27,81,243,729... has the sum of the digits as 9.
 But in the given options no number has the sum of the digits as 9. so the given options may be wrong.

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add all the respective digits........and if the sum is divisible by 3 then that no.is also divisble by three...or any case i.e.power...etc.......for e.eg in this case the correct ans is 6504===6+5+0+4==15====1+5==6 and 6 is divisible....hence that no is power of 3....

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  • Sep 23rd, 2010

The powers and multiples are different.
So the answer is 6504.
6504 is divisible by '3'. All other options are not divisible by '3'.
So 6504 is the power of '3'.

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  • Jul 17th, 2014

18 is divisible by 3 bt its not the power of 3.....
ans is D

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minni kumari

  • Sep 11th, 2014

we know that 3^1=3,3^2=9,3^3=27,3^4=81,3^5=243 and so on...
here see last digit 1,3,9,7 only it again repeated..
and in option there is only one that has last digit 3

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  • Sep 13th, 2014

none of them are the answer
the last option though looking promising is actually not a multiple of 3

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  • Feb 12th, 2015

c) 6504

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Aatish Singh

  • Feb 26th, 2015

In order to qualify as power of 3, last digit of the no. should belong to the set of (3,9,7,1).

And none of them do fulfills this criteria, So answer would be none of these.

Thanks & Regards

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  • May 6th, 2015

6504 because... sum of all numbers is divisible by 3.
6+5+0+4 = 15(which is divisible by 3)

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Prem kumar Uppu

  • Oct 26th, 2016

3 power 1=3;
3 power 1=
3 power 2=9
3 power 3 =27
3 power 4=81
3 power 5=243
Last number of 3power x is =1,3,7,9 this last numbers are likes 1,3,7,9 so answer is 9833 becoz there is no other last number in answer so answer is (9833)

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Vasu Sachdeva

  • Jul 7th, 2017

ANS is C) 6504
to calculate power of which one is power of 3 one had to add all digit and sum of digit must be divisible by 3
as in c) 6+5+0+4= 15 which is divisible 3.

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manjusha kaipu

  • Nov 9th, 2018

ans:-9833 how it is means check from the option:-1,2,3 options are not divisible 3 only 4 option divisible by 3

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John smith

  • Nov 25th, 2018

All options given are not a power of 3.

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  • Jan 22nd, 2019

9833 because of thats the only one number which is divisible by 3. We can check by using unit digit.

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