Kayalvizhi Oct 3rd, 2006 Let a, b, and c denote pencil, pen and eraser respectively.Given that the cost of one pencil, two pens and four erasers is Rs.22This can be written as, a + 2b + 4c = 22 ..........(1)Similarly, the cost of 5 pencils, 4 pens and 2 erasers is Rs. 32This implies .... 5a + 4B + 2c = 32 ......... (2)Adding (1) and (2), we get 6a + 6b + 6c = 54We need to find the value of 3a + 3b + 3c.Dividing by 2, we get 3a + 3b + 3c = 27.Hence, the cost of 3 pencils, 3 pens, and 3 erasers is Rs.27

sreeramdesikan Profile Answers by sreeramdesikan Jul 16th, 2008 Rs.27Add both the equation and divide the result by 2...

pranoti Profile Answers by pranoti Jan 30th, 2011 Let cost of 1 pencil, 1 pen and 1 eraser be x,y,z. now, x+2y+4z=22 - (1) 5x+4y+2z=32 - (2) subtracting (2)-(1); 4x+2y-2z=10 or 2x+y-z=5 -(3) subtracting (2)-(3); 3x+3y+3z=27 Answer=Rs27

prititripathi Profile Answers by prititripathi Mar 7th, 2011 x+2y+4z=225x+4y+2z=32add bth d eq. we get6x+6y+6z=54so 3x+3y+3z=27

Amit Kumar Sep 26th, 2018 15 rubbers cost ₹10.50.how many rubbers can be bought for ₹70? What will be the cost of 35 rubbers

## The cost of one pencil, two pens and four erasers is Rs.22 while the cost of five pencils, four pens and two erasers is Rs.32.How much will three pencils, three pens and three erasers cost?

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