A bus started from bus stand at 8.00am, and after 30 minutes staying at destination, it returned back to the bus stand.  The destination is 27 miles from the bus stand. The speed of the bus is 18mph.  In return journey bus travels with 50% fast speed. At what time it returns to the bus stand?

11.00am
This question is related to TCS Interview
  • Interview Candidate
  • 16
  • 19410

Showing Answers 1 - 16 of 16 Answers

munis

  • Jul 8th, 2005
 

it is very useful for me.please send the more  
aptitutde regarding the wipro,tcs,hcl to my e-mail id.thanking you.

  Was this answer useful?  Yes

babu

  • Aug 16th, 2005
 

Hi can u explain in brief

  Was this answer useful?  Yes

Jagdish Ahuja

  • Aug 17th, 2005
 

As the Bus is travelling 18mph it takes 1 & 1/2 hr to reach destination.  
Bus stays there for 1/2 hr.  
As in the return journy bus travelled with the 50% fast spped meance with the speed of 27mph. meance it took 1 hr to return 
For total journy it took 1&1/2+1/2+1hr=3 hr. 
therefore 8+3 =11  
Bus returns as 11 a.m.

SAROJINI

  • Jan 29th, 2006
 

It was good.plz send me questions like this.

  Was this answer useful?  Yes

vineet

  • Apr 8th, 2006
 

bus started at 8 am stays in destination 30 min

its speed 18mph

distence 27m

bus travels 50% of fast speed

time=d/v=27/18=3/2h=1h 30m

after 50%

time=(27/(9+18))=1h

tot time 1h+ih 30m+30m=3h

ans=11am

Harikumar

  • Sep 22nd, 2006
 

Initiall start time -- 8.00 am

start  ----------------------------------- destination

                  ( distance --> 27 milies), (speed -18mph)

so time- distance/speed , i.e 27/18 hrs  ->3/2 ---> 1.5 hrs --> bus will reach the destination at 9.30 am .

Since it waits 30 min in destination .. time = (9.30+.30)-->10.00 am

so ,the bus starts from destination at 10.00 am

while travelling back speed  is 50% higher than initiall , so 18+50% 0f 18 -->18+9-->27 mph, so timetaken -->27/27-- 1 hr.. so it will reach back in 10.00 am + 1 hr --> 11.00 am(Ans)

M.I.Abuthagir

  • Aug 11th, 2007
 

Cannot be 11.00 A.M.

It is 1.00 P.M.

Time taken for onward jpurney is 1.5 hrs.

Stay is 0.5 hrs.

Return journey is 3 hrs.

Adding 5 hrs with starting time, bus will reach at 1.00 P.M

  Was this answer useful?  Yes

Hirs_belive_apti

  • Sep 25th, 2008
 

Total time taken by it is following :


1.5 (to reach at destination) + 0.5 ( talking halt at station) + 1 (return with 50% speed)

so the total time taken by it is 3 hr

current time is 8.00 a.m + 3 hr = 11 a.m.

So 11 a.m. is the right answer

  Was this answer useful?  Yes

Give your answer:

If you think the above answer is not correct, Please select a reason and add your answer below.

 

Related Answered Questions

 

Related Open Questions