How to swap low-order byte & the high order byte in an integer without using temporary variable?for ex: int a=20;It is represented in bits as (i.e 16 bit format)since integer is of two bytes00000000 00010100i want the answer as00010100 00000000ie 5120 as the answer

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uddin2000

  • Sep 13th, 2006
 

Hi,

  Can we write a program like this

 void main(void)
 {
  int a=20;
  printf("%dn",a);
   a= (a<<8) | (a>>8);
  printf("%dn",a);
 }

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BIJOYA

  • Sep 13th, 2006
 

Better will be no = ( ( no & 0xff ) << 8) | ( no >> 8 )

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Anand Krishnan

  • Oct 24th, 2006
 

i think we can use this code in function

 int i=52;

 asm{

      rol i,8

}

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NHKR

  • Oct 30th, 2006
 

void swaploworder(){ unsigned int r=20; unsigned short *p; printf("Inside swaplowordern"); printf("the size of short is %dn",sizeof(short)); p=(short*)&r; printf("The value of r is %dn",r); printf("The value at upper half is %dn",*p); printf("The value at lower half is %dn",*(p+1)); *p=*p+*(p+1); *(p+1)=*p-*(p+1); *p=*p-*(p+1); printf("The value at upper half is %dn",*p); printf("The value at lower half is %dn",*(p+1)); printf("the new value of r is %dn",r);}

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Arup Ratan Banerjee

  • Jan 29th, 2007
 

1) int x=5; int y =100; x=x ^ y; y=y^x; x=x^y; printf("%d , %d ", x,y);2) int x=5; int y=100; x=y-x; y=y-x; x=y+x; printf("%d , %d", x,y);

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