Consider the following programmain(){unsigned int i=10;while(i>=0) { printf("%u",i) i--; }}How many times the loop will get executed

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ak

  • Aug 4th, 2006
 

11 times

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S.Sabarinathan

  • Sep 8th, 2006
 

Dear Friends, It will never end because the i is unsigned it will never reach the nagative value.

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G.C.V.Rajesh

  • Sep 30th, 2006
 

It becomes an infinite loop.

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ajay

  • Oct 5th, 2006
 

yes its an infine loop program good one anyways

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APPU

  • Feb 1st, 2007
 

It results an infinite loop

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mirror_vinita

  • Jul 14th, 2009
 

The loop will never get executed because of compilation error odf semicolon at the end of printf Statement.

If that is solved then the loop will execute infinitely.....

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mirror_vinita

  • Jul 14th, 2009
 

The loop won't be executed because of semicolon at the end of printf statement is not available.

Suppose if we have it then it will execute infinitely.

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anoophp_777

  • Jul 15th, 2009
 

Since int is Unsigned, the value of i does not go below zero. Hence the condition in the loop is always true and hence, its an infinite loop.

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