There are n urns and m balls. If we put 3 balls in each urn 3 balls will be excess. If we put 4 balls in each urn 1 urn will be excess. Find no. of Urns (or) Balls?

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  • Jun 29th, 2006

there r 2 urns and 9 balls.


  • Jun 30th, 2006

Hi Arvind,

Can u plz explain how u got this answer

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A.Ravi kumar

  • Jun 30th, 2006

There r 7 urns and 24 balls.sol:7 urns 3 in each implies 21 r filled an d 3 r left4 in each implies 6 urns r filled and 1 urn is left.

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  • Jul 2nd, 2006

From the problem we can find derive an equation ,

3n+3 = m and

4n+1 = m .

That is total number of balls = Number of balls in 'n' urns + excess balls

When we solve this, we will get 2 urns and 9 balls.

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  • Jul 6th, 2006

   eqs1: total ball 3n+3

   eqs2: total ball 4(n-1)

so,   3n+3 = 4n -4

0r,    n = 7

so 7 urns, 24 balls

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joseph vasant prkash

  • Jul 7th, 2006

The number of balls should be divisable by both 3 and 4. The numbers which are divisable by 3 and 4.

12 -> here the no of urns shoud be 3 at first case, but it is not suitable for the next case.

24 -> here the no of urns should be 7 at the first case, and it also satisfies the second case 24/4=6, so 1 urn will be remaining. . . .

Hence Answer is There are 24 Balls and 7 Urns.

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  • Jul 16th, 2006

hi  vidhya the method u did is correct but the equation 4n+1 is not equal to no of balls the equation is 4(n-1) plz check it out

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  • Jul 21st, 2006

There are 7 urns and 24 balls

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manali mandal

  • Jul 25th, 2006

m-3=3*n...........(1) (n-1)*4=m.........(2) so, no of urns =7and no of balls =24

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  • Aug 19th, 2006

the no of urns is 2 and the no of balls is 9

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  • Aug 21st, 2006

7 urns and 24 balls

let 3m+3=0

and 4m+1=0

then by solving we

the answer as so

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  • Sep 27th, 2006


 n=no. of Urns

and m= no of ball

now, 3n+3=m   and   4n+1=m

solving this two we get n=2(urns)  and  m= 9(balls)

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