A.Ravi kumar Jun 30th, 2006 There r 7 urns and 24 balls.sol:7 urns 3 in each implies 21 r filled an d 3 r left4 in each implies 6 urns r filled and 1 urn is left.

Vidhya Jul 2nd, 2006 From the problem we can find derive an equation ,3n+3 = m and 4n+1 = m .That is total number of balls = Number of balls in 'n' urns + excess balls When we solve this, we will get 2 urns and 9 balls.

sreedeep Jul 6th, 2006 eqs1: total ball 3n+3 eqs2: total ball 4(n-1)so, 3n+3 = 4n -40r, n = 7so 7 urns, 24 balls

joseph vasant prkash Jul 7th, 2006 The number of balls should be divisable by both 3 and 4. The numbers which are divisable by 3 and 4. 12 -> here the no of urns shoud be 3 at first case, but it is not suitable for the next case. 24 -> here the no of urns should be 7 at the first case, and it also satisfies the second case 24/4=6, so 1 urn will be remaining. . . . Hence Answer is There are 24 Balls and 7 Urns.

RITU Jul 16th, 2006 hi vidhya the method u did is correct but the equation 4n+1 is not equal to no of balls the equation is 4(n-1) plz check it out

manali mandal Jul 25th, 2006 m-3=3*n...........(1) (n-1)*4=m.........(2) so, no of urns =7and no of balls =24

Arindam Sep 27th, 2006 let n=no. of Urnsand m= no of ballnow, 3n+3=m and 4n+1=msolving this two we get n=2(urns) and m= 9(balls)

MERLIN DAVIS Profile Answers by MERLIN DAVIS Jun 6th, 2008 what to do with 2 answers?both 2&9 and 7&24 are practically right.

m_manic Profile Answers by m_manic Questions by m_manic Dec 10th, 2009 There n urns and m balls.3n + 3 = m4n + 1 = mSove this we will get n = 2 and m = 9

## There are n urns and m balls. If we put 3 balls in each urn 3 balls will be excess. If we put 4 balls in each urn 1 urn will be excess. Find no. of Urns (or) Balls?

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