shibaji.paul

 Profile Answers by shibaji.paul 

• Apr 20th, 2006

 

I think the syntax is incorect in the for loop of the change function, it sould have atleast a closing ')'.

Secondly, if the function defination is given after the function calling, then the proper prototype of the function must be declared before the calling of the function, other wise compiler declares a default prototype by considering each parameters as well as the return type as integer, which leads into the compiler error "type mismatch in redeclaration of the function".

Ravi Bhsuhan Raiya

• May 2nd, 2006

 

In this program, we have syntax error in function (change). the for loop is not properly ended.

brunda_testing

 Profile Answers by brunda_testing 

• May 25th, 2006

 

Actually *b means its pointer ,that means it points to the address ,for an address we can't add a value because i is an integer

Mitul Surti

• May 31st, 2006

 

dude the pointer declarations are allllll fine coz *(b+i) is equivalent to b[ i ]wats wrong is1) the for loop declaration for sure2) by default functions return value is int, hence your function should return a value else it hsould be declared void explicitly

mitul surti

• May 31st, 2006

 

well all the pointer declarations are perfectly OK coz *( b + i ) is equivalent to b[ i ]well 2 things are wrong about d prog1) for loop declaration2) by default the returntype of a function is int..hence as the function does not return type..it should be explicitly declared as void ..as it is considered int by default..and will return a compile time error

taransidhu

• Jun 1st, 2006

 

ok if we ignore some syntax mistakes than the purpose of the function is to add 5 to each element of aaray as we are passing addresses of each element any change in value of array elements in function will be reflected in main also

 as mr Mitul Surti has told already that *(b+i) is equivalent to b[ i ]so

*(b+i) = *(b+i)+5;  means

b[ i ]=b[ i ]+5;

umesh936

 Profile Answers by umesh936 

• Sep 7th, 2006

 

for(i=0;i *(b+i) = *(b+i)+5;

see the statement

can any body tell me what i*(b+i) means

*(b+i) = b[i] : i agree

bt i*(b+i)=ib[i]

wht does it mean?

2nd reason )offcourse for loop is not properly ended

gpreddy

 Profile 

• Nov 8th, 2006

 

The error is in int i;for(int i=0;i<=4;i++)here i declared twice : the remaining errors are may be typo errors.

chaitanya

• Oct 21st, 2007

 

First lets get the code ryt..

#include "stdio.h"

void change(int *b,int n)
{
  int i;
  for(i=0;i   *(b+i) = *(b+i)+5;
}

int main()
{
 
  int a[]={2,4,6,8,10};
  int j;
  change(a,5);
  for(j=0;j<=4;j++)
    printf("n %d",a[j]);
 return 0;
}

may be the question was asked to test the return values in the calle function rather than syntax errors, so this program does reflect the added 5 to the array since its pass by reference rather than a pass by value.

hope it helps,

chaitanya gudipati