we can calculate the length of an integer array by the following code

int array = {1,3,45,6,56};

size = sizeof(array)/sizeof(int);

Hi ,

# include < stdio.h >
# include < conio.h >

void accstrn();
int a [30];   // its a predefined array of 30 allocations.
int  c ;                // counter variable.
void main()

{

 clrscr();

 accstrn();

 printf ( " The length of the Int Array is %d ",c);
 
 getch();

}

void accstrn()
{
 

  for ( int i=0 ; i < 30 ; ++i )
 {
  scanf (" % d ", & a[i]);
  
  if ( a[i] != 0 )
 
  {
 
    c = i;
   
   accstrn ();
  }
  else
  {
   

   return (c);
  }
 }
}

Regards,

Rishi

NULL is never added to any array since NULL is a pointer value. Typically it is

#define NULL (void*(0))

THere is no way to get the size of an array unless it is statically allocated and the header that includes it defines the size or it is in the same module.

HEADER.H

extern int a[];

CCODE.C

int n = sizeof(a);  // Returns n = 4 (pointer size)

int b[10];

int m= sizeof(b); // Returns m= 10 * sizeof(int)

Null Pointer is used for the recogniation of the strings. But to calculate the length of the integer array, simpaly we can use a clunter while inserting the value to the array and we can calculate the lenght.

Suppose

int *arr,i;

scanf("%d",&arr[i]);

counter++;