C - What would be the output of the following program? main() { const int x=5; int *ptrx; ptrx=&x; *

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C | Question 184 of 453

What would be the output of the following program?
main()
{
const int x=5;
int *ptrx;
ptrx=&x;
*ptrx=10;
printf("%d",x);
}

A) 5
B) 10
C) Error
D) Garbage Value

Total Answers and Comments: 11

Last Update: March 19, 2008

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Best Rated Answer

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Submitted by: louisyang

It depends on compiler.

In C++, it is not allowed to convert const int* to int*. So error

In C, it is ok, and i = 10; So dont use C compiler, it is time to use C++ compiler, just my one cent

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January 23, 2006 23:44:25

javedamaan21

Member Since: January 2006 Contribution: 2

RE: What would be the output of the following program?...

answer will be option (c).that is error.

Here we are trying to modify the constant value of x to 10 which should not be done.. so it will pop an error saying that cant modify a constant value

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January 24, 2006 08:56:55

kiranck007

Member Since: January 2006 Contribution: 11

RE: What would be the output of the following program?...

actually there will be comiler warning....but the value will be changed when u run the program

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Overall Rating: -2

March 17, 2006 05:21:12

Bhanu

RE: What would be the output of the following program?...

Ans: a) 5

Hello

Here we are assiging address of x to ptrx so we are not changing

the value of X So value of x is 5

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March 29, 2006 14:26:11

louisyang

Member Since: December 2005 Contribution: 4

RE: What would be the output of the following program?...

It depends on compiler.

In C++ it is not allowed to convert const int* to int*. So error

In C it is ok and i 10; So dont use C compiler it is time to use C++ compiler just my one cent

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2 0

Overall Rating: +2

April 11, 2006 04:11:38

satyanarayana.p

RE: What would be the output of the following program?...

hai all

Ans is 10;

Because we r using pointer to chane the value of the variable.So it should be ans is 10.

if u give ptr 10 in above question then ans is 5 only

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February 29, 2008 12:49:44

Rahul_chandra

Member Since: February 2008 Contribution: 3

RE: What would be the output of the following program? main() { const int x=5; int *ptrx; ptrx=&x; *ptrx=10; printf("%d",x); }

here an error because we can not convert const int * to int *

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February 29, 2008 12:53:10

Rahul_chandra

Member Since: February 2008 Contribution: 3

RE: What would be the output of the following program? main() { const int x=5; int *ptrx; ptrx=&x; *ptrx=10; printf("%d",x); }

it is not a matter of compiler it is matter of our fundamental
so fundamental is that we can not change constant .
so there is error. if talk to turbo compiler then run this program without error.
and i m telling that turbo compiler has sevrak mistakes that confuse a begginer.

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February 29, 2008 12:54:43

Rahul_chandra

Member Since: February 2008 Contribution: 3

RE: What would be the output of the following program? main() { const int x=5; int *ptrx; ptrx=&x; *ptrx=10; printf("%d",x); }

it is not a matter of compiler it is matter of our fundamental
so fundamental is that we can not change constant .
so there is error. if talk to turbo compiler then run this program without error.
and i m telling that turbo compiler has sevral mistakes that confuse a begginers.

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March 04, 2008 14:27:10

bismitapadhy

Member Since: July 2007 Contribution: 5

RE: What would be the output of the following program? main() { const int x=5; int *ptrx; ptrx=&x; *ptrx=10; printf("%d",x); }

Ans is 10

const int x; means x is constant.We can't change value of x but we can chage *ptrx.

But still we will get a warning suspecious pointer conversion.

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March 05, 2008 06:39:54

#10

ravidhingra89

Member Since: March 2008 Contribution: 1

RE: What would be the output of the following program? main() { const int x=5; int *ptrx; ptrx=&x; *ptrx=10; printf("%d",x); }

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