C - main(){ int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p prin

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C | Question 140 of 436

main()
{
int i, j, *p;
i = 25;
j = 100;
p = &i; // Address of i is assigned to pointer p
printf("%f", i/(*p) ); // i is divided by pointer p
}

A) Compile error
B) 1.00000
C) Runtime error.
D) 0.00000
Explanation: Error because i/(*p) is 25/25 i.e 1 which is int & printed as a float, so abnormal program termination, runs if (float) i/(*p) -----> Type Casting.

Total Answers and Comments: 9

Last Update: August 12, 2008

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December 15, 2005 05:05:23

NAVNISH JAIN

RE: main(){ int i, j, *p; i = 25;

it is compiler dependent.

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December 15, 2005 05:08:13

NAVNISH JAIN

RE: main(){ int i, j, *p; i = 25;

it is compiler dependent.

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January 18, 2006 03:52:30

C_learner

Member Since: January 2006 Contribution: 6

RE: main(){ int i, j, *p; i = 25;

It will mostly give run time error and not compile time error....

Also use typecasting i.e. use (float)i/(*p); and you will get 1.0000.. as the answer

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May 15, 2006 18:46:35

sravanan

RE: main(){ int i, j, *p; i = 25;

compiler error.because division is not possible usinsg pointers.

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May 16, 2006 02:56:15

shweta

RE: main(){ int i, j, *p; i = 25;

hi,

this gives runtime error.

i tried to run program in vc with .c extension file.

it gives runtime error

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March 03, 2007 00:02:36

noname2000

Member Since: February 2007 Contribution: 1

RE: main(){ int i, j, *p; i = 25;

i try compile with turbo C++ and it print out a garbage value. No error.

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January 13, 2008 04:59:48

Kalpitgdeewan

Member Since: December 2007 Contribution: 1

RE: main(){ int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p}

it gives 0.00000 as the output when we run it :P

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January 16, 2008 05:37:24

santhigkinterview

Member Since: January 2008 Contribution: 5

RE: main(){ int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p}

Run time Error – Floating point not loaded.

printf("%f", i/(*p) ); // i is divided by pointer p

by doing type casting (float)i/(*p) we can avoid this error.

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August 12, 2008 11:45:42

sourabh_t

Member Since: August 2008 Contribution: 2

RE: main(){ int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p}

C. Runtime Error

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