C - main() { int i; clrscr(); printf("%d", &i)+1; scanf("%d", i)-1; }

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C | Question 133 of 453

main()
{
int i;
clrscr();
printf("%d", &i)+1;
scanf("%d", i)-1;
}

A) Runtime error. Access violation
B) Compile error. Illegal syntax
C) None of the above
D) Runtime error
Explanation: printf( ) prints address/garbage of i, scanf() dont have & sign, so scans address for i +1, -1 dont have any effect on code.

Total Answers and Comments: 10

Last Update: December 23, 2008

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December 30, 2005 00:08:28

pandi

RE: Answer

Ans : Complier time error

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January 05, 2006 09:17:55

srinivasan

RE:

ans is -12

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January 09, 2006 19:37:35

sujatham

Member Since: January 2006 Contribution: 142

RE: ans is (c)

Here printf() gives garbage value of i.

Here scanf() has no effect on function main.

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January 17, 2006 09:48:48

Chump

RE:

Note that there is & which means it probably prints the address of i...n my guess is that + 1 has no effect on the output...
n regarding scanf - there is no & symbol...so still it will accept a value but not store it in i n my guess is that -1 has no effect on the code....
any comments

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January 23, 2006 13:29:52

Vijay

RE:

Hey guys look at the code carefully it will give a segmentation fault as scanf expects the address of the variable in which the value will be scanned.

so the code should be like

scanf( d &i) -1;

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March 15, 2006 05:08:22

sreelu

RE:

ans is -12because it prints address of i.

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March 27, 2006 08:56:19

vishal

RE: Runtime error. Access violation

answer will be A)

As scanf expects address of i.

As soon as user enters any no. for i compiler will try to access memory location equal to value of i and it will give acess voilation on windows and core dump on Solaris/Linux.

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June 11, 2006 08:25:43

dev07

Member Since: May 2006 Contribution: 1

RE:

answer is A) Runtime error. Access violation.

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May 27, 2008 07:14:07

punjalasampath

Member Since: May 2008 Contribution: 1

RE: main() { int i; clrscr(); printf("%d", &i)+1; scanf("%d", i)-1; }

runtime error