# CATG. : DIFFICULT+ CALCULATIVE40 men can finish a job in 40 days.5 men leave after every 10th day.find the no. of days. the job will be done ?

#### utpat_rahul Profile Answers by utpat_rahul

• Nov 4th, 2005

I need the answer of this question.

#### zub_p Profile Answers by zub_p

• Nov 17th, 2005

#### pravin_vaidya Profile Answers by pravin_vaidya

• Nov 22nd, 2005

50.761 which is equivalent to 51

Therefore Days Required is 51

#### pravin_vaidya Profile Answers by pravin_vaidya

• Nov 22nd, 2005

51 days

#### jay kumar mishra

• Dec 9th, 2005

1 man in 1 day can do 1/1600 work

1/1600 * (40*10+ 35*10 + 30*10 ..........) = 1

40*10 + 35*10 + 30*10 +25*10 +20*10 +15*6.67  = 1600

no. of days = 56 2/3

#### rahul16agarwal

• Jul 14th, 2006

40 men   40 days      1 work

1             1                 1/1600 work

(I )  case    for ten days        40       10       ? work            remaining= 3/4

(II) case                               35      10      35/160           rem=(3/4 ? 35/160)=17/32

(III) case                             30       10        3/16            rem=(17/32 ? 3/16)=11/32

(IV) case                            25                10                5/32            rem=3/16

(V) case                               20                 10               2/16          rem=1/16

(VI) case                            15                  1                   15/1600

15                 6.6                 (15*6.6)/1600 = 1/16

Therefore total  10+10+10+10+10+6.6=56.6~57

#### meera_987 Profile Answers by meera_987

• Apr 22nd, 2008

from the above solution,

in the case : 20 men , 10 days , work done= 1/8 and remaining work=1/16

next case: 15 men, 10 days, work done= 15/160=3/32=1/16

remaining work= (1/16)-(1/16)

so the answer wud b 10+10+10+10+10+10 = 60