naina

• Sep 26th, 2005

 

2nd digit is the smallest
so it must be 1.

3rd digit is the largest
so it can be 9 and the first digit is 8.

1st digit is greater than the
addition of 4th and 5th digit.
so it can be 1,2;2,1;3,4;4,3;2,3;3,2;2,4;4,2  but 5th digit is between the 1st and 2nd digit and half of the 4th digit so it can be 4 and 2 and so we should  have  1 more prime no.

so the third digit cannot be 9 it should be 8 and the first digit is 7.

so the number is 71842.

pravin

• Sep 27th, 2005

 

as said in question 1 is not considered as prime number so i think the 7 is only prime number present in the ans

pravin

• Sep 27th, 2005

 

sry the answer is correct 2 and 7 are prime numbers

suku

• Sep 28th, 2005

 

why cant it be 70842?,if i consider 0 as the smallest number?

vinay karalkar

• Feb 23rd, 2006

 

70821 is also possible

1)7,2 only 2 prime nos, 0 is not considered as prime as divisible by any number  with remainder 0

2)1st digit 7 is 1 less than 3rd i e 8

3)3rd digit is largest =8

4)1st digit 7> sum of 4th and 5th i e 2+1=3

5)5th digit 1 is between 1st and 2nd i e betn 7 and 0

6)2nd digit is smallest i e 0

dinesh

• Nov 4th, 2006

 

ans : 63742 (sure) and 37 happens to be my lucky number.

rohit.innova

 Profile Answers by rohit.innova 

• Jun 7th, 2007

 

60721 is also ans
3rd digit largest=7
second digit smallest =0
1st digit ==(3rd dgt-1) && (6 is >2+1)
5th dgt is 1  0<1<6
5th dgt is half of 4th digit

7,2 are 2 prime nos 1 is not prime acc to problem

Mrinal Kumar

• Aug 23rd, 2007

 

Considering 1 as the least digit in the no,only possible solution is :-

71842

Considering 0 as the least digit in the no, possible solutions can be:-

70821
60721
50621

Plz correct me if did any mistake!!!

aminath latheefa

• Nov 16th, 2015

 

As said in Question 1 is not considered as prime number so I think the 7 is only prime number present in Ans