A cube is painted black. It is divided into 125 equal cubes. Find the number of cubes, which have at least 2 sides painted black?

This question is related to Wipro Interview

Showing Answers 1 - 11 of 11 Answers

Harpreet

  • Nov 27th, 2005
 

80 squares have atleast 2 of their sides painted

  Was this answer useful?  Yes

mayank bajpai

  • Feb 7th, 2006
 

125-[5*9+9*4]=44

  Was this answer useful?  Yes

sap2000

  • Apr 21st, 2006
 

8 cubes will have 3 sides each painted in Black.

36 cubes will have 2 each painted in Black.

Correct Answer is 44 cubes will have 2 or more sides painted in black.

  Was this answer useful?  Yes

b prakash babu

  • Jun 21st, 2006
 

44 cubes

36 [2sides]+ 8 [3sides]

  Was this answer useful?  Yes

Sandeep

  • Jun 22nd, 2006
 

Here is the Formulae
This is usefull when the whole cube is painted with same color
All the Eight corners of the cube will have 3blacks
All the edges of the cube but look at extreme corners of the edge they have 3 blacks but we want 2 blacks hence we have to subtrace 2 from every edge and hence the formulae is (n-2) * 12
Here has it is given 125 means (5 * 5 * 5) hence n=2 i.e 3 * 12 = 36
Atleast 2 blacks means 2 or more blacks hence ==> 36 + 8 = 44 (answer)

Sooraj Prabhakaran

  • Jan 1st, 2007
 

2 sided cube formula -->>12(n-2)

3 sided cube formula -->>always 8

...  12(5-2)+ 8

     ==36 + 8 =44

8 cubes, one at each corner of the cube, will have 3 faces black.
3 cubes along each edge of the cube will have 2 faces black. There are 12 such edges & hence 12*3=36 cubes have 2 faces black.
So total no of cubes having at least 2 faces black is 8+36 = 44 nos.

  Was this answer useful?  Yes

Give your answer:

If you think the above answer is not correct, Please select a reason and add your answer below.

 

Related Answered Questions

 

Related Open Questions