Let days taken by A x days

Then days taken by B 6x days (since he is 6 times slower)

So the difference 6x - x 5x days.

But this difference 100 days

Therefore 5x 100 implies x 20 days

So A takes 20 days to finish a job and B takes 120 days to finish a job.

if they work together total time taken 1/(1/20+1/120) 120/7 17 1/7 days

A completed work in 100 days before and A is 6 times faster than B..

let total days to work is n.

A 6B;

A (n-100) days taken to complete the work;

where as B n days ;

A (B-100)

therefore B A+100;

A 6(A+100);

A 6A+600;

-600 6A-A

-600 5A

A -600/5

A 300

B 400;

Since a is 6 times faster 6A B

ie if b compeletes the work in n days B n

& A (n-100)

ie 6(n-100) n

5n 600

n 120

ie B's work 120

A works 120-100 20

1/A 6/B B 6A A B-100 solving 2 equations

A 20 B 120 (1/20)+(1/120) 7/120

so he takes 120/7days