varun

• Jul 3rd, 2005

 

for a program 
int main(int argc, char **argv) .... 
^^^^ 
sizeof(int) number of arguments are possible 
hence 32767 args are possible for a 32 bit computer

Partha006

 Profile Answers by Partha006 

• Jun 30th, 2006

 

wowowow nice calculation and great answer.. hatsoff

Ashish Agrawal

• Nov 19th, 2006

 

NEVER!If you are deciding the numbers of arguments on the basis of size of int in 32 bit compiler, it should be 2^31-1. that is almost square of 32767.And The memory allocated to argv is from RAM. SO do you really think compiler allocates memory holding 2^31-1 strings of any size!

karthisiva

 Profile Answers by karthisiva 

• Dec 21st, 2010

 

As far as I know, it depends on the first argument which represents the number of arguments.
If argc is 2 bytes in length, 65535 strings can be passed.
If argc is 4 bytes in length, 4294967295 strings can be passed.
In Both the cases first one is for program name.
And the total length should not exceed the heap size.