Mr. and Mrs. Aye and Mr. and Mrs. Bee competed in a chess tournament.Of the three games played:

A)In only the first game were the two players married to each other.

b)The men won two games and the women won one game.

c)The Ayes won more games than the Bees.

d)Anyone who lost game did not play the subsequent game.Who did not lose a game?

Mrs.Bee did not lose a game
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thana

  • Aug 27th, 2005
 

HI, 
I cannot find out most of the answers. Can anyone please suggest me a good book on aptitude.l

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Gagan

  • Feb 3rd, 2006
 

AM=Mr. Aye

AF= Mrs. Aye

BM=Mr. Bee

BF=Mrs. Bee

The possible sequence of matches can be :

AM(Win) Vs.AF

AM(win) Vs. BM

AM Vs. BF(win)      Hence Mrs. Bee never lose. 

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rohith

  • Feb 28th, 2006
 

mr and mrs bee has wone 2 games winning the series

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Jyoti

  • Oct 13th, 2006
 

Hi,

R.S.Agarwal and Baron this two books are good for apittude........

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Google

  • Oct 27th, 2006
 

In three games, men won more games than women (therefore, at least 2), and Ayes won more games than Bees (therefore, at least 2). Also, if a player lost, s/he did not play the next game. Therefore, Mr. Aye must have won his game (Ayes 1, Bees 0; Men 1, Women 0). Mrs. Aye is out.For the Ayes to win 2 games, Mr. Aye must have won the second game. (Ayes 2, Bees 0; Men 2, Women 0)In order for a woman to win a game, Mrs. Bee must have won her game against Mr. Bee (Ayes 2, Bees 0; Men 2, Women 1).So Mr. Aye never loses. Duh.

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Al

  • Nov 2nd, 2006
 

this puzzle is from george j. summers "puzzles and teasers'Answer is Mrs Bee,,, george has given a confusing and long explaination,, here is my versionMr aye beat mrs aye in first game (bee cant be playing since ayes are supposed to win more games, if one of them is out, then even if both ayes can win against the remaining bee, it violates the other conditions,, think,,,)now two casesmr aye vs mr bee >> winner mr aye (aye win more games than bee)mr aye vs mrs bee >> winner mrs bee (women win atleast one game)hence mrs bee playes the finalist and beat him,,,,

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swarna

  • Dec 26th, 2006
 

1-Mr and Mrs aee (Mr Aee wins)

2-Mr Aee and Mr Bee (Mr Aee wins)

3-Mr Aee and Mrs Bee (Mrs Bee)

Men wins twice,Women once.

1st game played by couples Mr and Mrs Aee

Abhishek Anand

  • Apr 22nd, 2015
 

BM(win) vs BF
AM vs BM(win)
BM vs AF(win)
AF never loses a game.

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Gaurav.khurana

  • Apr 25th, 2015
 

@anand you missed one condition that Aye win > Bee win
In your solution , B winning > A winning
so the solution as listed above is M=male F = female
1) AM(win) -- AF ( first match is couple)
2) AM(win) - BM ( second match aye win 2 matches out of 3)
3) BF(win) - AM ( AF and BM cannot play as they lost matches. also women won 1 match)
hence Mrs Bee (BF) did not loose a game

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suman

  • May 21st, 2016
 

BM VS BF(WIN)
AM(WIN) VS BF
AM (WIN) VS BM
So,AM never loses a game..
*it is not mandatory that everyone has to participate in the game,so AF didnt take part in that game

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