How would you print just the 25th line in a file (smallest possible script please)?

Showing Answers 1 - 2 of 2 Answers

Rishi

  • Jun 6th, 2005
 

sed -n '25p' filename.txt

Vijay Roy

  • Jan 25th, 2006
 

echo "Enter User Name "read nameecho "Enter passwd "stty -echoread passstty echo sqlplus -s $name@oracle/$pass<

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Vijay Roy

  • Jan 25th, 2006
 

echo "Enter User Name "read nameecho "Enter passwd "stty -echoread passstty echo sqlplus -s $name@oracle/$pass<

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ruchi sharma

  • Oct 13th, 2006
 

 head -25 filename|tail -1

punitha

  • Mar 7th, 2007
 

cat -n filename | grep '25'

bhanu_tadiboina

  • May 17th, 2007
 

head -25 file| tail -1 goes wrong because if some one deletes some lines even then it gives last line as 25th line.
so the right option is

tail +25 file| head -1

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Sri

  • Jul 11th, 2007
 

I think both the command results with same answers

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Abhijeet

  • Jul 13th, 2007
 

tail -n +25 | head -1 OR
head -n 25 | tail -1

s4srinivas

  • Oct 15th, 2007
 

cat -n <filename>|grep '25'

goes wrong if the file has 25 in anyof the lines

srinath prakashnaidu

  • Oct 26th, 2007
 

head -25 |tail -1

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Following command will give the required output.

head -25 <filename> | tail -1


Head will get the first 25 lines, whereas tail will get the last line of the 25 lines (i.e. 25the line).

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my_thoughts

  • Feb 14th, 2010
 

Both of them would mean the same.
You ruled out first option saying that someone might delete the starting lines.
The same case would be with 2nd option if someone deletes the ending lines.

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Furkan

  • Mar 30th, 2012
 

cat ( x in file)
do
if [ $line -eq 25 ]
then
echo $line
fi
done

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Giridhar

  • Mar 31st, 2012
 

head -25 filename | tail -n +25

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Mike

  • Apr 8th, 2012
 

head -25 filename | tail -1

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Mo

  • Apr 20th, 2012
 

sed -n 25p filename or cat -n | grep "^5"

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Govind Kailas

  • May 10th, 2012
 

A simple perl one liner to print only the 25th line

Code
  1. perl -ne $. == 25 && print && exit

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Patricia

  • May 25th, 2012
 

in bash:

cat $filename | awk {print $25 }

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Jessmon

  • Jun 1st, 2012
 

Code
  1. head -n25 $filename |tail -n1

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SGN

  • Jun 12th, 2012
 

send -n 25 p

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Gaurav

  • Oct 2nd, 2012
 

awk NR==25 {print $0} file

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AP

  • Nov 11th, 2012
 

file + 25 | head -1

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Sudha

  • Dec 7th, 2012
 

head -25 file | tail -1
sed -n {25p} file
sed {26,$d} file | sed {1,24d}

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Sudhin

  • Jan 11th, 2013
 

head -25 | nl | tail -1

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Abhishek

  • Feb 21st, 2013
 

awk NR==25

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Rajendra Prasad

  • Jun 5th, 2013
 

sed -n 25p filename(a.txt)

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Rajendra Prasad

  • Jun 7th, 2013
 

head -25 filename|tail -1

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Piyush K

  • Aug 25th, 2014
 

cat -n Filename | grep ^25

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Inesh

  • Aug 25th, 2014
 

sed -n 25p filename

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Dibya

  • Aug 26th, 2014
 

• sed -n 10p
• cat -n | sed -n 10p
• sed -n 10p
• head -10 | tail -1
• sed -n 1,10p | tail -1
• cat | head -10 | tail -1
• head -10 | tail +10

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Manas

  • Sep 16th, 2014
 

head -25 |tail -1

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Rakesh

  • Sep 18th, 2014
 

sed -n 25p file_name

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Anirban

  • Feb 2nd, 2015
 

Code
  1. show kth line:

  2. cat file|tail -n +k |head -1

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Don Alom

  • Mar 18th, 2015
 

awk { if (NR==25) print $0} filename

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vikas

  • Mar 20th, 2015
 

sed 25!d

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Ashka Shah

  • Apr 1st, 2015
 

head -25 | tail -1

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Mohd Haroon

  • Jul 7th, 2015
 

awk NR==25 filename

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Ajay Barik

  • Jul 9th, 2015
 

sed -n 25p filename

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santosh

  • Aug 3rd, 2015
 

awk -F "" NR == 25 {print $0}

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aniket

  • Aug 12th, 2015
 

head -25 file.txt | tail -1

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kian

  • Aug 23rd, 2015
 

sed -n 25 p file.txt

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gaurav Sharma

  • May 16th, 2017
 

awk NR==25 aa.sh

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