A nand gate becomes ___ gate when used with negative logic ?

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SathyaGopi

  • Jun 1st, 2005
 

NAND gate becomes AND gate when used with negative logic. 
 
NAND gate turth table(with -ve logic) 
0 0 0 
0 1 0 
1 0 0 
1 1 1 -> this is truth table of AND gate 

poornima.V

  • Aug 25th, 2005
 

C this website. Ans is Nor gate. that is convert one tozeroes and vice versa. 
 
http://www2.ele.ufes.br/~ailson/digital2/cld/chapter2/Ex02.doc.html

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Neha Sinha

  • Oct 31st, 2005
 

It becomes an and gate

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ankit garg

  • Jan 6th, 2006
 

my lord.it becomes a AND Gate ....such a simple question.

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Anjum

  • Mar 21st, 2006
 

When used with negative logic means that the inputs are inverted.

If the inputs of a nand gate are inverted and given, the output will be an OR of the inputs. De morgans law (A'.B')' = A + B

geek

  • Apr 18th, 2006
 

OR gate is the right answer

adhisrijina

  • May 30th, 2006
 

ANS is nor gate

negative logic means a high is interpreted as low and vice-versa

poornima is right

sateesh

  • Jun 11th, 2006
 

it is so simple it becomes an AND gate when we use negative logic becuase NAND means that Negaive AND

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sudhanshu

  • Jul 10th, 2006
 

The NAND gate becomes a "OR" gate because
(a'.b')' = ((a+b)')' = a+b (by De-Morgan's)

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pearlin

  • Jul 28th, 2006
 

it is NOR ofcourse

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djdansays

  • Aug 7th, 2006
 

it is NOR gate. Lets analyse how.

In positive logic 0s are considered low and 1s as high voltages. In negative logic 0s are high and 1s are low. Now the truth table for Nand is

A B Y         A(V) B(V) Y(V)-> positive logic

0 0 1         low    low   high

0 1 1         low   high   high

1 0 1         high   low   high

1 1 0         high   high  low

Now when used as negative logic then the truth table will be

A B Y

1 1 0

1 0 0

0 1 0

0 0 1

hence it is NOR gate.

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abhilash

  • Sep 12th, 2006
 

an and gate with negative logic becomes nor gatetruth table for and gate is0 0 - 01 0 00 1 01 1 1we get 1 1 1 0 it is for nor gate

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Anitha

  • Oct 13th, 2006
 

OR gate

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hardik parikh

  • Oct 27th, 2006
 

hi , it will become AND gate at there.

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Ben

  • Nov 1st, 2006
 

First of all, a NAND gate is not (a'.b'), it is (a.b)' -- that is, (a'+b'). When you negate this, you get (a'+b')' which you can then de-morgan to get (a.b). So a NAND gate become AND

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nagalakshmi

  • Dec 4th, 2006
 

it becomes 'OR' gate..so simple apply Demorgan's laws..u will get 'OR'.

bexdeep

  • Aug 17th, 2008
 

Yes i think it becomes nor gate because using a negative logic doesn't mean doing any mathematically. it means just suposing zero to be one and viceversa

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SUBASH

  • Sep 11th, 2012
 

NOR gate

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MANISH MANCHANDA

  • Jun 16th, 2016
 

NOR gate

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