{geshibot language="c"}#include #include int main() { int a=10; void *p; p=&a; clrscr(); printf("%u",*p); getch(); return; }{/geshibot} I know that this program is wrong as error is shown on compiling it. Anyone please provide a simple program using Void pointer in C. Thanks in advance :)

Ashok Kumar Orupalli

• Sep 3rd, 2012

You have to typecast void pointer to int as *(int*)p;

Code
#include<stdio.h>
#include<conio.h>
int main()
{
 int a=10;
 void *p;
 p=&a;
 clrscr();
 printf("%u",*(int*)p);
 getch();
 return 0;
}

Sereche

 Profile Answers by Sereche Questions by Sereche

• Jul 9th, 2012

Your error is on line 9, where youve attempted to dereference a pointer to void (the expression *p). You can only dereference typed pointers. The solution you are probably looking for would be to repl...

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