A number when divided by D leaves a remainder of 8 and when divided by 3D leaves a remainder of 21 . What is the remainder left, when twice the number is divided by 3D? a) 13 b) cannot be determined c) 3 d) 42

MBA

• Aug 11th, 2011

Suppose the no. is a
a = Dx +8 ...1
a = 3Dy + 21 ...2
So from 1 & 2 we get
D(x-3y) = 13
13 is prime so x-3y has to be 1
let x = 4 and y = 1
We get a = 60
2a = 120
So 120 when divided by 3D = 39
we get remainder as 3
So answer is 3

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abi

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A) 3

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