Ankit Saraf

• Feb 14th, 2016

 

sed -n 1p FileName | cut -d" " -f1

ARJIT PANDEY

• Feb 17th, 2016

 

awk -F " " {print$1} filename|head -1

Gaurav.khurana

 Profile Answers by Gaurav.khurana 

• Apr 2nd, 2016

 

@ankit but how about picking up the first 10 files

Gaurav.khurana

 Profile Answers by Gaurav.khurana 

• Apr 2nd, 2016

 

@arjit the answer is correct from single file.. but in question we have to pick the first 10 files also

Rakesh Kumar

• Apr 22nd, 2016

 

head -n 10 filename
it shows 1st 10 files

shrey shekhar

• Apr 26th, 2016

 

sed -n 1p file name--will print the first line of that particular file name

Saumyajit Mishra

• May 15th, 2016

 

head -1 filename | cut -d " "-f1

Manvendra

• Jun 4th, 2016

 

awk {print FNR, $0} filename1 filename 2 ..... filename10 | awk $1 == "1" {print $2} | cut -c1

Bala

• Jul 26th, 2016

 

awk NR>=1&&NR<=10{print $1} filename

Raans

• Sep 6th, 2016

 

for a in `ls -lrt|head -10|awk {print($9)}
do
head -1 $a|awk {print($1)]
done

Anupam Kumar

• Oct 27th, 2016

 

cd test
for i in $(ls -1rt | head -10)
do
awk {print $1} $i
done

Pankaj

• Nov 17th, 2016

 

head -1 | cut -d "" -f1
and in order to print 1 word
head -1 | cut -c1 #where no of lines is 1 that we want to print

akhila

• Jul 7th, 2017

 

sed -n 1 p file | cut -f1 -d

firoz khan

• Aug 27th, 2017

 

Sed -n 1 p file | cut -f1 -d | head -10

Asish

• Dec 22nd, 2017

 

Head -1 *.* | head -10 | ask { print $1} or cut -d -f1