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Write a shell script that accept 7 numbers in loop

write a shell script that accept 7 numbers in loop,then make a sum of this numbers. then count the numbers that are greater than 250 ?
Asked by: angel rayan | Member Since Jun-2012 | Asked on: Jun 3rd, 2012

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ardiansyah

Answered On : Jul 5th, 2012

Code
  1. #!/bin/bash
    2. 

  2. total=0
    3. 

  3. c=0
    4. 

  4. for a in {1..3};
    5. 

  5.   do
    6. 

  6.         echo -n "Write a number : "
    7. 

  7.         read i
    8. 

  8.         if [ $i -ge 250 ] ; then let "c=c+1"
    9. 

  9.         fi
    10. 

  10.         let "total = i + total"
    11. 

  11.   done
    12. 

  12. echo "total = $total"
    13. 

  13. echo " > 250 = $c "

  
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