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What is out put of C++ code?

Code
  1. class base
    2. 

  2. {
    3. 

  3.   public:
    4. 

  4.          virtual void display(int i = 10)
    5. 

  5.          {
    6. 

  6.            cout<<"Base class display with i = "<<i<<endl;
    7. 

  7.          }
    8. 

  8.  
    9. 

  9. };
    10. 

  10.  
    11. 

  11. class derived : public base
    12. 

  12. {
    13. 

  13.   public:
    14. 

  14.           void display(int i = 20)
    15. 

  15.          {
    16. 

  16.            cout<<"Derived class display with i = "<< i <<endl;
    17. 

  17.          }
    18. 

  18.  
    19. 

  19. };
    20. 

  20.  
    21. 

  21. int main(int argc, char *argv[])
    22. 

  22. {
    23. 

  23.      base *bptr = new derived;
    24. 

  24.      bptr->display();
    25. 

  25.        
    26. 

  26.       return 0;
    27. 

  27. }
    28. 

  28.  
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Asked by: ak.nextptr | Member Since Jan-2012 | Asked on: Mar 21st, 2012

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Showing Answers 1 - 11 of 11 Answers
Vip

Answered On : May 1st, 2012

Derived class display with i = 10

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Shobhit Chaturvedi

Answered On : May 12th, 2012

dervie class function display

  
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bluesky28

Answered On : May 15th, 2012

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Derived class display with i = 20

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windowcleaner

Answered On : May 30th, 2012

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Derived class display with i = 10

  
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saum almas

Answered On : May 30th, 2012

Derived class display with i = 10

  
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Deepak

Answered On : Jun 13th, 2012

Derived class display with i=10 because in virtual functions do pass the default arguments if you are passing then made both versions of function with same default argument

  
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Mahesh

Answered On : Jun 20th, 2012

Derived class display method with i=20, because assigning derived object to base class reference. so derived class display method will call

  
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Teodor

Answered On : Aug 6th, 2012

It indeed displays "Derived class i=10". What happens is that through polymorphism, the base * obj = new derived() object can have access to the body of the overridden method, but its signature containing the default value for the "i" parameter is taken from the base class. That's because of the run-time vtable mechanism: the function is called for a base object, but the vtable fetches the implementation for the overridden one, from the derived class. Hence the odd output.

  
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abhimanyu

Answered On : Aug 9th, 2012

it will be 20

  
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panreth

Answered On : Aug 23rd, 2012

View all answers by panreth

Answer is : "derived class display with i=10"

  
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reddy-

Answered On : Apr 10th, 2013

Overriding function default argument takes more precedence ,Hence based class default argument 10 will be initialized to i.So i value holds 10 will be printed for this call with derived count statement.

  
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