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Array Values Algorithms

How many values can be held by an array with dimensions A(0:n), B(-1:n,1:m), C(-n:0,2)?
Asked by: francislawrance | Member Since Jan-2009 | Asked on: Jan 4th, 2009

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imithya

Answered On : Aug 16th, 2009

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A(0:n) = n+1 elements

-1 specifies that the array indexing starts at '-1' uptill 'n'. Therefore, there can be "n-(-1)+1 = n+2" rows in the array. Each of this row may hold upto m (m-1+1) elements. Therefore, B(-1:n, 1:m) = (n+2)*(m) elements

Similarly,
C(-n:0, 2) = (n+1)*(3) elements

  
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