Analytical - Four Friends A, B, C and D are living in a hostel. One day A’s uncle came and gave him a box of ladd

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Four Friends A, B, C and D are living in a hostel. One day A’s uncle came and gave him a box of laddoos, According to their rule whatever they get will be equally divided among them. So A divided the laddoos into four equal parts and he ate his part. Then B came to the room and he divided the laddoos into four equal parts and A and B ate their part. Then C came to the room he divided the laddoos into four equal parts and he ate his part. Then at the last D came to the room he also divided the laddoos into four equal parts and he ate his part. The number of laddoos D ate was 3.

1. How many laddoos did A eat?

2. How many laddoos did B eat?

3. How many laddoos did C eat?

4. How many laddoos were there in the box altogether?

Total Answers and Comments: 20

Last Update: August 19, 2009 Asked by: himani

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Best Rated Answer

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Submitted by: vreswar

Hi All,
    My approach is quite simple:

Say there are x laddoes.
A shares x/4 each to himself, B,C,D. n eates it      (A=x/4)
B comes and shares x/4*4 to each and eat    (A=x/4+x/16, B=x/16)
C comes , shares x/4*4*4 to each and eat (A=x/4+x/16, B=x/16, c=x/64)
D comes, shares x/4*4*4*4 to each and eat (A=x/4+x/16, B=x/16, c=x/64, D=x/256)

as its given D eats 3: x/256 =3 => x=768 (Clear)

let us check it with c = x/64 => 768/64 = 12

B = x/16 =>768/16 = 48

A = x/4 + x/16 => 192+48 = 240

A=240, B=48,C=12 D=3.

Above answer was rated as good by the following members:
ghf13, bandlamudi, asingha

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November 27, 2007 01:42:33

deepa

RE: Four Friends A, B, C and D are living in a hostel....

calculation is as below:

D 3*4 12

C 12*4/3 16

B (16*2)/4 8

A 32*4/3 42.6

Hence A's share is 10.6+8
B ate 8 Laddoos
C ate 4

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December 23, 2007 12:20:42

vivekjain17

Member Since: December 2007 Contribution: 3

RE: Four Friends A, B, C and D are living in a hostel. One day A’s uncle came and gave him a box of laddoos, According to their rule whatever they get will be equally divided among them. So A divided the laddoos into four equal parts and he ate his part.

A eat 71 laddos
B eat 39 laddos
C eat 15 laddos
Total laddos were 128

Approach Since D eat 3 laddos that means when he came he saw there were 12 laddos (3*4)That means when C came in he must have seen 48 (12*4) laddos and divided then in four parts each which left 12 for D. Now important point to note here is that when C came he saw 48 laddos which were actually for C and D 24 each because if B has divided in 4 equal part he would have eat 24 give A as 24 and left 24 each for C and D. That gives us step that When B came in must have seen 96 (24*3) laddos. Which were actually for B C and D. That gives us answer that when A got the box there should be 128 laddos which he divided in 4 equal parts of 32 each. So if we sum up laddos which A must have eat it will be (32+24+12+3)

B (24+12+3) and C (12+3) and D we know it’s 3

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February 08, 2008 13:11:15

charenbe

Member Since: November 2007 Contribution: 2

d 3
3*4 12
a. b . c d ate 3 sweet 3

12*4 48/3 16
a b c ate 16each

16*4 64/2 32
a b 32each

32*4 128
a 128

a 128+32+16+3
a 179

b 32+16+3 51

c 16+3 19

d 3
total 252

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March 16, 2008 05:15:07

satya1288

Member Since: January 2008 Contribution: 6

Let number of laddoos be n
Now
n A 3A

3A 3A/4(B) 9A/4

9A/4 9A/16(C) 27A/16

27A/16 27A/64(D) 81A/64

Given D 3

>A 64/9

B (3*64) / (9*4) 16/3

C (9*64) / (16*9) 4

Total No of Laddoos A+3A 256/9

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March 28, 2008 05:52:19

vreswar

Member Since: March 2008 Contribution: 1

Hi All
My approach is quite simple:

Say there are x laddoes.
A shares x/4 each to himself B C D. n eates it (A x/4)
B comes and shares x/4*4 to each and eat (A x/4+x/16 B x/16)
C comes shares x/4*4*4 to each and eat (A x/4+x/16 B x/16 c x/64)
D comes shares x/4*4*4*4 to each and eat (A x/4+x/16 B x/16 c x/64 D x/256)

as its given D eats 3: x/256 3 > x 768 (Clear)

let us check it with c x/64 > 768/64 12

B x/16 >768/16 48

A x/4 + x/16 > 192+48 240

A 240 B 48 C 12 D 3.

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May 13, 2008 10:22:59

venky_vision2020

Member Since: May 2008 Contribution: 3

no: of laddoos A ate is 240
no: of laddoos B ate is 48
no: of laddoos c ate is 12
total no: of laddoos in the box is 768

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May 30, 2008 13:01:58

peterson35

Member Since: May 2008 Contribution: 1

Total laddood is 24

d ate 3
so when D comee remaining laddoos 12

3/4 of x is 12
so x is 16
similarly

do it it comes to 24.

Am I right?

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June 08, 2008 17:15:29

sarathchowdary

Member Since: June 2008 Contribution: 2

total 20 laddos

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July 16, 2008 01:41:26

rtandon

Member Since: July 2008 Contribution: 2

1. How many laddoos did A eat?

18.66667

2. How many laddoos did B eat?
8
3. How many laddoos did C eat?
4
4. How many laddoos were there in the box altogether?
3

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July 16, 2008 05:40:07

#10

rtandon

Member Since: July 2008 Contribution: 2

1. How many laddoos did A eat?
18.66
2. How many laddoos did B eat?
8
3. How many laddoos did C eat?
4
4. How many laddoos were there in the box altogether?
42.66

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