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Both guptha and sinhas have two young sons whose ages are under eleven. the names of the boys, whose ages round off to the nearest year are all different, are rajesh , praveen, lalitm and pratap. Taking the ages of the boys only to the nearest year, the following statements are true.
Rajesh is three years younger than his brother is
Praveen is the oldest.
Lalit is half as old as one of the gupta boys.
Pratap is five years older than the younger sinha boy.
The total ages of the boys in each family differ by the same amount today as they did five yeasrs ago.
How old is each boy, and what is each boys family name ?

  
Total Answers and Comments: 4 Last Update: January 01, 2009   
  
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September 07, 2005 04:23:11   #1  
HariHaran N        

RE: Both guptha and sinhas have two young sons whose ages are under eleven. the names of the boys, whose...
Guptha:
Pratap-10
Rajesh-7
Sinhas:
Praveen-9
Lalitm-5

 
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October 30, 2005 16:13:42   #2  
Varun        

RE: Both guptha and sinhas have two young sons whose ages are under eleven. the names of the boys, whose

How is the above solution possible when it is mentioned

praveen is the oldest.............

i think answer is:

Sinha's

Rajesh : 2

Lalit : 5

Gupta's

Praveen : 10

Pratap : 7


 
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November 25, 2005 06:11:29   #3  
Nishant Joshi        

RE: Both guptha and sinhas have two young sons whose a...

From given condition it is easy 2 find out which son belongs 2 which family

Gupta Sinha

Praveen-10 Lalit-5

Pratap -7 Rajesh-2 (5-3)


 
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January 01, 2009 09:48:43   #4  
Bhoomika sharma Member Since: December 2008   Contribution: 40    

RE: Both guptha and sinhas have two young sons whose ages are under eleven. the names of the boys, whose ages round off to the nearest year are all different, are rajesh , praveen, lalitm and pratap. Taking the ages of the boys only to the nearest year, t

gupta:
pratap x year y/2+2 year
praveen y year

sinha:
lalit y/2
rajesh y/2-3

(y)-(y/2+2) (y/2)-(y/2-3)
y/2 5
y 10

> y 10year


 
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