nagesh

• Jul 25th, 2006

 

i guess the answer to this is : "4"

1/3 were infront of u ...... (1/3)x

and 3/4 of them .......here this means (3/4) of (1/3)  ....... (1/3)(3/4)x=(1/4)x

(the reason to think like this is because if we take out 1/3 people then the remaining people r 2/3 which is less than 3/4 hence i took 3/4 of 1/3)

that is (3/4)x people were in merry go round......

that is least could be x=4

hence the least mumber of people  are (3/4)x4 = 3  ........... and taking her into consideration it becomes 3+1=4 ........

well this is what i think is the solution ....

r

• Jul 26th, 2006

 

answer can b 2

Archana.G

 Profile 

• Aug 14th, 2006

 

Ans: 13

Sashikala

• Oct 5th, 2006

 

12

hari

• Nov 9th, 2006

 

what is the answer 2 or 4 or 13 plz solve the puzzle

chaitra

• Nov 14th, 2006

 

i guess the answer to this is : "4" let x be the total no of people xcluding the person mentioned above. 1/3 were infront of u ...... (1/3)x and 3/4 of them .......here this means (3/4) of (1/3)  ....... (1/3)(3/4)x=(1/4)x (the reason to think like this is because if we take out 1/3 people then the remaining people r 2/3 which is less than 3/4 hence i took 3/4 of 1/3) (1/3)x+(1/4)x=(7/12)x so totally there r (7/12)x+1 people in tne merry go round min value of x is 12 hence answer is 13

amikat

 Profile Answers by amikat 

• Jun 12th, 2008

 

merry go round is circular so its not possible for x no. of ppl to be ahead of u or to be behind  since all r sitting in a circle..so determining the no. of ppl on a merry go round is not possible...